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3 years ago

A compound has a pH of 3 what is the [H+] concentration?

Chemistry

1 answer:

Allisa [31]3 years ago

8 0

Answer: 0.001 M

Explanation:

pH is the negative logarithm of hydrogen ion concentration in a solution. Mathematically, pH is expressed as

pH = -log(H+)

where H+ is hydrogen ion concentration

So, 3 = -log(H+)

(H+) = Antilog (-3)

(H+) = 0.001

Thus, [H+] concentration is 0.001 M

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The combustion method used to analyze for carbon and hydrogen can be adapted to give percentage N by collecting the nitrogen fro

12345 [234]

Answer:

The percentage of N in the compound is 0.5088

Explanation:

Mass of compound = 8.75 mg = 8.75×1000 = 8750 g

Mass of N2 = number of moles of N2 × MW of N2 = 1.59 × 28 = 44.52 g

% of N in the compound = (mass of N2/mass of compound) × 100 = (44.52/8750) × 100 = 5.088×10^-3 × 100 = 0.5088

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3 years ago

why is the concentration of helium increased in some gas mixtures that divers breath in order to reduce the partial pressure of

sdas [7]

Answer:

Because of oxygen toxicity.

Explanation:

Oxygen toxicity.

Oxygen has been known to cause central nervous system (CNS) toxicity when the pressure gets higher. This toxicity can cause convulsions, and this can cause the diver to drown.

The current standard maximum safe oxygen working pressure is 1.4 atm ppO2. This is equal to 56.5m/185′ when breathing air (21% O2 / 79% N). Below that depth the fraction of oxygen in a breathing gas must be reduced, and in order to maintain this maximum pressure of 1.4 ppO2, Helium must be added.

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3 years ago

stbank, Question 075 Get help answering Molecular Drawing questions. Compound A, C6H12 reacts with HBr/ROOR to give compound B,

Law Incorporation [45]

Answer:

Explanation:

In this case we want to know the structures of A (C6H12), B (C6H13Br) and C (C6H14).

A and C reacts with two differents reagents and conditions, however both of them gives the same product.

Let's analyze each reaction.

First, C6H12 has the general formula of an alkene or cycloalkane. However, when we look at the reagents, which are HBr in ROOR, and the final product, we can see that this is an adition reaction where the H and Br were added to a molecule, therefore we can conclude that the initial reactant is an alkene. Now, what happens next? A is reacting with HBr. In general terms when we have an adition of a molecule to a reactant like HBr (Adding electrophyle and nucleophyle) this kind of reactions follows the markonikov's rule that states that the hydrogen will go to the carbon with more hydrogens, and the nucleophyle will go to the carbon with less hydrogen (Atom that can be stabilized with charge). But in this case, we have something else and is the use of the ROOR, this is a peroxide so, instead of follow the markonikov rule, it will do the opposite, the hydrogen to the more substituted carbon and the bromine to the carbon with more hydrogens. This is called the antimarkonikov rule. Picture attached show the possible structure for A. The alkene would have to be the 1-hexene.

Now in the second case we have C, reacting with bromine in light to give also B. C has the formula C6H14 which is the formula for an alkane and once again we are having an adition reaction. In this case, conditions are given to do an adition reaction in an alkane. bromine in presence of light promoves the adition of the bromine to the molecule of alkane. In this case it can go to the carbon with more hydrogen or less hydrogens, but it will prefer the carbon with more hydrogens. In this case would be the terminal hydrogens of the molecules. In this case, it will form product B again. the alkane here would be the hexane. See picture for structures.

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3 years ago