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Papessa [141]
3 years ago
10

How has the modern research in chemistry impacted society

Chemistry
1 answer:
Anastaziya [24]3 years ago
7 0

Answer:

Here is ur answer;

  • Modern research in chemistry has impacted society by allowing us to make informed decision. With the knowledge of chemistry, you can form better opinions about today's news. You will be able to distinguish the truth from the lies in environmental reporting and better understand the meaning of a chemical spill.
  • Modern research in chemistry can lad to technologiesthat aim to benefit the environment, conserve and produce energy, improve human life, and expand our knowledge of the universe. Modern research in chemistry has impacted society by gathering data from afar analyse matter that is brought back to the earth.
  • The industrial application of chemistry directly affects our daily lives --- what to eat, what we wear, our transport, the technology we use, how we treat our illness and how get electricity -- to name a few. Research is constantly deepening our understanding of chemistry and leading to new discoveries.
  • Chemistry is essential to meeting our basic needs of food, clothing, shelter, health, energy and clean air, water and soil. Chemical technologies enrich our quality of life in numerous ways by providing new solutions to problems of health, problems in health, materials and energy usage... For better or for worse, everything is chemical.

<h3>Hope it helps!!</h3>

<em>Then</em><em>;</em>

<h3><em>Please</em><em> </em><em>mark me as brainliest</em><em>!</em><em>!</em><em>!</em></h3>

<em>✨</em><em>Thanks</em><em>!</em><em>!</em><em>!</em><em>!</em>☺<em>✨</em>

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What happens when lead nitrate and potassium iodide are mixed?
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Answer:

Explanation: A yellow precipitate o lead iodide is formed. see equation of reaction below: 2KI + Pb(NO3)2 → PbI2 + 2K(NO3)2

Th PbI2 is the insoluble yellow precipitate

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The average person in the United States is exposed to the following amount of radiations annually. Rank the following source of
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Calculate the volume in mL of 0.279 M Ca(OH)2 needed to neutralize 24.5 mL of 0.390 M H3PO4 in a titration.
Vsevolod [243]

The volume of the 0.279 M Ca(OH)₂ solution required to neutralize 24.5 mL of 0.390 M H₃PO₄ is 51.4 mL

<h3>Balanced equation </h3>

2H₃PO₄ + 3Ca(OH)₂ —> Ca₃(PO₄)₂ + 6H₂O

From the balanced equation above,

  • The mole ratio of the acid, H₃PO₄ (nA) = 2
  • The mole ratio of the base, Ca(OH)₂ (nB) = 3

<h3>How to determine the volume of Ca(OH)₂ </h3>
  • Molarity of acid, H₃PO₄ (Ma) = 0.390 M
  • Volume of acid, H₃PO₄ (Va) = 24.5 mL
  • Molarity of base, Ca(OH)₂ (Mb) = 0.279 M
  • Volume of base, Ca(OH)₂ (Vb) =?

MaVa / MbVb = nA / nB

(0.39 × 24.5) / (0.279 × Vb) = 2/3

9.555 / (0.279 × Vb) = 2/3

Cross multiply

2 × 0.279 × Vb = 9.555 × 3

0.558 × Vb = 28.665

Divide both side by 0.558

Vb = 28.665 / 0.558

Vb = 51.4 mL

Thus, the volume of the Ca(OH)₂ solution needed is 51.4 mL

Learn more about titration:

brainly.com/question/14356286

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