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zalisa [80]
1 year ago
10

Compare the atomic sizes of sodium and magnesium. Explain. ​

Chemistry
1 answer:
mihalych1998 [28]1 year ago
5 0

<u>Answer:</u>

Sodium atom is larger than Magnesium atom.

<u>Explanation:</u>

Looking at the electronic configurations of Sodium and Magnesium:

_{11}Na: 1s^2 2s^2 p^6 3s^1\\\\_{12}Mg : 1s^2 2s^2 p^6 3s^2 ,

we can see that they both have their valence electrons in the 3rd shell.

But because Magnesium has a higher nuclear charge of +12 because of its 12 protons than that of Sodium's +11, the nucleus of Magnesium attracts its outer electrons more strongly than Sodium does. This makes the Magnesium atom smaller.

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Approximately 2.5 kg of carbon dioxide gas are produced for every liter of gasoline burned in an automobile gasoline engine. Cal
uranmaximum [27]
125 mile *1gallon/35 mi = 135/35 = (27/7) gallon gasoline 

27/7 gallon * 1 L/0.264 gallon = 14.6 L  gasoline

14.6 L gasoline * 2.5kg CO2/1L gasoline= 36.5 kg CO2

36.5 kg CO2 * 1lb/0.454 kg = 80.4 lb

Answer: 80.4 lb CO2

6 0
2 years ago
A student sees an absorbance a=1.140 for his solution that has a concentration of c=1.50*10-4 m using 0.50 cm cuvette. what is t
777dan777 [17]

The molar extinction coefficient is 15,200 M^{-1} cm^{-1}.

The formula to be used to calculate molar extinction coefficient is -

A = ξcl, where A represents absorption, ξ refers molar extinction coefficient, c refers to concentration and l represents length.

The given values are in required units, hence, there is no need to convert them. Directly keeping the values in formula to find the value of molar extinction coefficient.

Rewriting the formula as per molar extinction coefficient -

ξ = \frac{A}{cl}

ξ = \frac{1.140}{1.5*10^{-4}*0.5 }

Performing multiplication in denominator to find the value of molar extinction coefficient

ξ = \frac{1.140}{0.000075}  

Performing division to find the value of molar extinction coefficient

ξ = 15,200 M^{-1} cm^{-1}

Hence, the molar extinction coefficient is  15,200 M^{-1} cm^{-1}.

Learn more about molar extinction coefficient -

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6 0
1 year ago
Which equation agrees with ideal gas law?
Julli [10]
Https://www.gstatic.com/education/formulas2/355397047/en/boyle_s_law.svg
8 0
2 years ago
Mercury is a liquid meteal but it is not hard? how can we say it is a metal
NNADVOKAT [17]
What's the problem ? Hardness is not the definition of a metal. You need to expand your thinking. EVERY element is solid, liquid, and gas, over different ranges of temperature ... including all of the metals. There are only TWO elements that are liquid AT ROOM TEMPERATURE, and mercury is one of them. But on a mild day at the south pole, mercury is solid too.
7 0
3 years ago
Compound a is an alkene that was treated with ozone (followed by dms) to yield only 4-heptanone. Draw the major product that is
olga nikolaevna [1]

Alkenes on reacting with ozone results in the formation of ozonide which undergo reductive  cleavage in presence of dimethyl sulfide to form carbonyl compounds (aldehyde or ketone). Whereas in presence of hydrogen peroxide it undergoes oxidative cleavage to form carboxylic acids or ketones.

Since, A alkene yields 4-heptanone only on treatment with ozone and DMS thus, it implies that both the chains on the side of the double-bond are similar the product is 4-heptanone that means the double bond is present between the chains at the 4th carbon. Therefore the structure of compound A is 4,5-dipropyloct-4-ene.

The reaction is as shown in the image.

The reaction of A with m-CPBA (meta-perchlorobenzoic acid) followed by aqueous acid H_3O^{+} is shown in the image.

m-CPBA (meta-perchlorobenzoic acid) is a peracid and forms epoxides on reacting with alkenes.

5 0
3 years ago
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