Heat the sulfuric acid solution and adding copper carbonate in it.
<h3>Improvement require in this experiment</h3>
The method could be improved by heating sulfuric acid solution and add copper carbonate into the solution of sulfuric acid. Add the copper carbonate until it is present in excess amount. After that filter the extra amount of copper carbonate so in this way the blue copper sulfate crystals are produced.
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To determine the number of moles of a gas, we need to have an expression that relates the pressure, temperature and volume of the system. For simplification, we assume that this gas is ideal so we use the equation PV=nRT. We calculate as follows:
PV=nRT
n = PV / RT
n = 235000(1.48x10^-4) / (8.314)(40+273.15)
n = 0.01336 mol
"Decaying swamps are covered with seawater" step ONLY occurs in the formation of coal.
<u>Option:</u> B
<u>Explanation:</u>
Coal production continues in regions of swampy wetlands because groundwater is near to or just above the topsoil. Because of this, organic matter is created quickly by the flora present-faster even than it can be broken down. Layers of organic matter are deposited in these areas, and then buried.
Based on the plants and circumstances present, the mechanism that produces coal varies somewhat in various areas but the ultimate method is similar. Coal production has two primary phases: peatification, and coalification. It is a solid black, readily combustible fossil fuel containing a large quantity of carbon-based material-about 50 percent of its mass.
Answer:
gravity
Explanation:
Gravity is an example of the force of attraction between two objects that have mass.
Answer:
7.61 liters
Explanation:
From the question,
Applying Charles law formula,
V₁/T₁ = V₂/T₂...................... Equation 1
Where P₁ = initial volume of of air, V₂ = Final volume of air, T₁ = Initial Temperature of air, T₂ = Final Temperature of air.
make V₂ the subject of the equation
V₂ = (V₁×T₂)/T₁............... Equation 2
Given: V₁ = 5 liters, T₁ -35 °C = (-35+273) K = 238 K, T₂ = 89°C = (89+273) K = 362 K
Substitute these values into equation 2
V₂ = (5×362)238
V₂ = 1810/238
V₂ = 7.61 liters