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Alex17521 [72]
3 years ago
12

46.0 g of barium nitrate is dissolved in 360 g of water. What is the percent concentration of the barium nitrate solute in the s

olution?
Pls help with answer I don’t get it
Chemistry
1 answer:
avanturin [10]3 years ago
8 0

The percent concentration of the Barium nitrate : 11.33%

<h3>Further explanation</h3>

The concentration of a substance can be expressed in several quantities such as moles, percent (%) weight/volume,), molarity, molality, parts per million (ppm) or mole fraction. The concentration shows the amount of solute in a unit of the amount of solvent.

\tt \%mass=\dfrac{mass~solute}{mass~solution}\times 100\%

mass solute=mass Barium nitrate(Ba(NO₃)₂)=46 g

mass solvent=mass water=360 g

mass solution=mass solute+mass solvent=46+360=406 g

\tt \%mass=\dfrac{46}{406}\times 100\%\\\\\%mass=\boxed{\bold{11.33\%}}

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Answer: Statements (A), and (C) are correct.

Explanation:

The statements that are true are as follows.

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What is the name of the ionic compound AlBr3?
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For the reaction
azamat

Answer:

Mass = 5.56 g

Explanation:

Given data:

Mass of Cl₂ = 4.45 g

Mass of NaCl produced = ?

Solution:

Chemical equation:

2Cl₂ + 4NaOH     →   3NaCl + NaClO₂ + 2H₂O

Number of moles of Cl₂:

Number of moles = mass/molar mass

Number of moles = 4.45 g/ 71 g/mol

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Now we will compare the moles of Cl₂ with NaCl.

                  Cl₂         :         NaCl

                    2          :          3

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Mass = 0.095 mol × 58.5 g/mol

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