Answer:
distance is 13 m for 100 dB
distance is 409 km for 10 dB
Explanation:
Given data 
distance r = 2.30 m 
source β = 115 dB
to find out 
distance at sound level 100 dB and 10 dB
solution
first we calculate here power and intensity and with this power and intensity we will find distance 
we know sound level  β  = 10 log(I/
)        ......................a
put here value (I/
) = 10^−12 W/m² and  β = 115
115  = 10 log(I/10^−12) 
so
I = 0.316228 W/m² 
and we know power = intensity × 4π r²    ...............b
power = 0.316228 × 4π (2.30)²
power = 21.021604 W
we know at 100 dB intensity is 0.01 W/m² 
so by equation b
power = intensity × 4π r² 
21.021604 = 0.01 × 4π r² 
so by solving r 
r = 12.933855 m    = 13 m 
distance is 13 m
and
at 10 dB intensity is 1 × 10^–11 W/m²
so by equation b 
power = intensity × 4π r² 
21.021604 = 1 × 10^–11 × 4π r² 
by solving r we get 
r = 409004.412465 m = 409 km