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Delvig [45]
3 years ago
15

How would you describe the connection between the amount of energy a type of electromagnetic wave has and how that wave is used

in technology and society
Chemistry
1 answer:
Mazyrski [523]3 years ago
7 0

Answer:

Uses of various electromagnetic waves depend on their relative energy.

Explanation:

The electromagnetic spectrum is the term used by scientists to describe the entire range of light that exists from radio waves to gamma rays. Electromagnetic waves is a wave of alternating electric and magnetic fields. The electromagnetic spectrum is a continuum of all electromagnetic waves arranged according to frequency and wavelength. The sun, earth, and other bodies radiate electromagnetic energy of varying wavelengths. Electromagnetic energy passes through space at the speed of light in the form of sinusoidal waves. The spectrum of waves is divided into sections based on wavelength. The shortest waves are gamma rays, which have wavelengths of 10^-6 microns or less. The longest waves are radio waves, which have wavelengths of many kilometers.

The application of various electromagnetic waves in science and technology depends on the energy of the wave. Electromagnetic waves that possess very high amount of energy are used in medical diagnosis, treatment of tumors, searching of baggage and detection of flaws in metal casting. Examples of such electromagnetic waves include gamma rays and xrays.

Some part of the electromagnetic spectrum possess energy enough to excite chemical bonds and produce spectra characteristic of certain functional groups in molecules. The ultraviolet and infrared rays fall into this category.

Some portion of the spectrum possesses very low energy and long wavelength and are mostly used for communication, mild medical diagnosis and resonance imaging/spectroscopy. Radio waves fall into this category.

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The answer is C, i just took the k-12 test~
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State what happens to the potential energy of a the substance during the interval BC *
Ratling [72]

Answer:

The potential energy decreases whereas the kinetic energy increases.

6 0
3 years ago
• We obtained the above 10.00-mL solution by diluting a stock solution using a 1.00-mL aliquot and placing it into a 25.00-mL vo
garik1379 [7]

Answer:

a) The relationship at equivalence is that 1 mole of phosphoric acid will need three moles of sodium hydroxide.

b) 0.0035 mole

c)  0.166 M

Explanation:

Phosphoric acid is tripotic because it has 3 acidic hydrogen atom surrounding it.

The equation of the reaction is expressed as:

H_3PO_4 \ + \ 3NaOH -----> Na_3 PO_4 \ + \ 3H_2O

1 mole         3 mole

The relationship at equivalence is that 1 mole of phosphoric acid will need three moles of sodium hydroxide.

b)  if 10.00 mL of a phosphoric acid solution required the addition of 17.50 mL of a 0.200 M NaOH(aq) to reach the endpoint; Then the molarity of the solution is calculated as follows

H_3PO_4 \ + \ 3NaOH -----> Na_3 PO_4 \ + \ 3H_2O

10 ml            17.50 ml

(x) M              0.200 M

Molarity = \frac{0.2*17.5}{1000}

= 0.0035 mole

c) What was the molar concentration of phosphoric acid in the original stock solution?

By stoichiometry, converting moles of NaOH to H₃PO₄; we have

= 0.0035 \ mole \ of NaOH* \frac{1 mole of H_3PO_4}{3 \ mole \ of \ NaOH}

= 0.00166 mole of H₃PO₄

Using the molarity equation to determine the molar concentration of phosphoric acid in the original stock solution; we have:

Molar Concentration =  \frac{mole \ \ of \ soulte }{ Volume \ of \ solution }

Molar Concentration = \frac{0.00166 \ mole \ of \  H_3PO_4 }{10}*1000

Molar Concentration = 0.166 M

∴  the molar concentration of phosphoric acid in the original stock solution = 0.166 M

6 0
3 years ago
What is the molarity of a solution that has 4.4 moles BaCl2 in 1.5 Liters of solution?
garik1379 [7]

Answer:

2.9 M

Explanation:

Step 1: Given data

Moles of barium chloride (solute): 4.4 moles

Volume of solution: 1.5 liters

Step 2: Calculate the molarity of barium chloride in the solution

The molarity is a way to quantitatively express the concentration of a solute in a solution. The molarity is equal to the moles of solute divided by the volume, in liters, of solution.

M=\frac{4.4mol}{1.5L} =2.9 M

7 0
2 years ago
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