Answer:
1.38×10^25 molecules
Explanation:
Applying n= (no. of molcules)/NA
23 = N/6.02×10^23
= 1.38×10^25 molecules
Answer:
B. Libra
Explanation:
Libra's range from September 23rd to October 22nd
<u>Answer:</u> The freezing point of solution is 2.6°C
<u>Explanation:</u>
To calculate the depression in freezing point, we use the equation:
Or,
where,
= 
Freezing point of pure solution = 5.5°C
i = Vant hoff factor = 1 (For non-electrolytes)
= molal freezing point depression constant = 5.12 K/m = 5.12 °C/m
= Given mass of solute (anthracene) = 7.99 g
= Molar mass of solute (anthracene) = 178.23 g/mol
= Mass of solvent (benzene) = 79 g
Putting values in above equation, we get:
Hence, the freezing point of solution is 2.6°C
3.8 mole Cl2
Explanation:
3.8molesC6H5Cl x 1moleCl2/ 1mole C6H5Cl
Answer:
all
Explanation:
it can be from all as some plants are hydrotrophic i.e. they get attracted to water but some get away from water. Same sunflower faces sun from morning to evening but some plants get burnt while in sun.
