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JulsSmile [24]
3 years ago
5

Describe how to draw the geometric mean in a right triangle

Mathematics
1 answer:
CaHeK987 [17]3 years ago
4 0
Answer: The height of the altitude from the hypotenuse to the vertex of the right angle is the geometric mean of the two segments formed on the hypotenuse.

The geometric mean of two numbers is the square root of the product of the numbers.

When you draw your altitude, you will divide the hypotenuse into 2 segments. The geometric mean of those two lengthsis also the height of the altitude.
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cricket20 [7]
A. she needs 81sq ft

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6 0
3 years ago
3x − 2y = −2
Lina20 [59]

Answer: C. -3y+14

Step-by-step explanation:

3x-2y=-2\\x+3y=14

Move 3y to ther right side.

3x-2y=-2\\x=-3y+14

So the answer is C. Because x = -3y+14.

7 0
3 years ago
Read 2 more answers
Differentiate the function. f(x) = ln(25 sin^2(x))
tigry1 [53]
Use the chain rule.
Let u = 25sin²(x), such that dy/dx = dy/du · du/dx

\frac{dy}{dx} = \frac{1}{25sin^{2}(x)} \cdot 50cos(x) \cdot sin(x)
\frac{dy}{dx} = \frac{2cos(x) sin(x)}{sin^{2}(x)}

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8 0
3 years ago
X - 10+ 9x = - 1 + 10x
Karo-lina-s [1.5K]

Answer:

<h2></h2><h2><u><em>the equation is false</em></u></h2>

<u><em></em></u>

Step-by-step explanation:

x - 10+ 9x = - 1 + 10x

-10 + 1 = -x - 9x + 10x

-9 = 0

the equation is false

7 0
1 year ago
Which expression is equivalent to (4x^(3)y^(5))(3x^(5)y)^(2)
marshall27 [118]

Answer:

(4x^3y^5)(3x^5y)^2 = 36*x^{13}y^7

Step-by-step explanation:

Given

(4x^3y^5)(3x^5y)^2

Required

The equivalent expression

We have:

(4x^3y^5)(3x^5y)^2

Expand

(4x^3y^5)(3x^5y)^2 = 4x^3y^5*9x^{10}y^2

Further expand

(4x^3y^5)(3x^5y)^2 = 4*9*x^3*x^{10}y^5*y^2

Apply laws of indices

(4x^3y^5)(3x^5y)^2 = 36*x^{13}y^7

8 0
3 years ago
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