Answer:
The equation which describes conservation of charge is 
Explanation:
The law of conservation charge states that for an isolated system that sum of initial charges is equal to sum of final charges, that is the total charge is conserved.
let the sum of initial charges = 
let the sum of the final charges = 
Therefore, the equation which describes conservation of charge is
The dog walked 5 meters backwards in the first 10 seconds, then 5 meters forward from 10-20 seconds. After 20 sec he was back where he started. Displacement (20sec) = zero.
Maybe friction..? my best answer.
Answer:
a. 4 m/s b. 0.2 V
Explanation:
a. Find the flow rate through a 3.00-cm-diameter pipe if the Hall voltage is 60.0 mV.
The hall voltage V = vBd where v = flow-rate, B = magnetic field strength = 0.500 T and d = diameter of pipe = 3.00 cm = 0.03 m
Since V = vBd
v = V/Bd given that V = 60.0 mV = 0.060 V, substituting the values of the other variables, we have
v = 0.060 V/(0.500 T × 0.03 m)
v = 0.060 V/(0.015 Tm)
v = 4 m/s
b. What would the Hall voltage be for the same flow rate through a 10.0-cm-diameter pipe with the same field applied?
Since the hall voltage, V = vBd and v = flow-rate = 4 m/s, B = magnetic field strength = 0.500 T and d' = diameter of pipe = 10.0 cm = 0.10 m
Substituting the variables into the equation, we have
V = vBd
V = 4 m/s × 0.500 T × 0.10 m
V = 0.2 V
Answer:
230.4kg
Explanation:
volume of the room = l× b×h
volume= 8×6×4
volume=192m3
density= mass/volume
hence mass= density × volume
mass= 1.2kgm-3 × 192m3
mass= 230.4kg
