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Elis [28]
3 years ago
7

An object on the moon feels lighter than the same object on earth. which statement explains this phenomenon?

Physics
1 answer:
natka813 [3]3 years ago
7 0

Answer:

B

Explanation:

cause

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1- A train travels 92 kilometers in 3 hours, and then 55 kilometers in 3 hours. What is its average speed?
Hunter-Best [27]
<h3>Answer:</h3>
  1. 24.5 km/h
  2. 4 17/27 m/s
  3. 11/3 m/s²
<h3>Explanation:</h3>

1. The average speed is the ratio of total distance to total time:

... speed = distance/time = (92 km +55 km)/(3 h +3h) = (147 km)/(6 h)

... = 24.5 km/h

2. speed = distance/time = (125 m)/(27 s) = 4 17/27 m/s

3. a = ∆v/∆t = (15 m/s -4 m/s)/(3 s) = 11/3 m/s²

8 0
3 years ago
While standing on the edge of the grand canyon, you see a rattlesnake and scream. You hear the echo of the scream off canyon flo
bezimeni [28]

Answer:

1904 m

Explanation:

\pink{\frak{Given}}\begin{cases} \textsf{ You scream after seeing a rattle snake  .}\\\textsf{Scream is heard after 11.2 s .} \end{cases}

Here we need to find out the depth of the canyon . When you will scream after seeing a snake , the sound produced will travel till the end of the canyon and after hitting the end , it will travel back to you .

  • So if the depth of the canyon is d (say) , then the total distance travelled by the sound wave will be d + d = 2d .

And we know that the speed of the sound is approximately 340m/s in air , so we can use the formula distance = speed * time to calculate the depth of the canyon . So ,

\sf \longrightarrow Distance = (Speed)(Time) \\

\sf \longrightarrow 2d = 340m/s * 11.2 s\\

\sf \longrightarrow d = \dfrac{340m/s * 11.2s}{2} \\

\sf \longrightarrow \boxed{\bf Depth_{canyon}= 1904m }\\

6 0
2 years ago
An electron and a proton have the same kinetic energy upon entering a region of constant magnetic field and their velocity vecto
kupik [55]

Answer: rp/re= me/mp= 544 * 10^-6.

Explanation: To calculate this problem we have to consider the circular movement by the electron and proton inside a magnetic field.

Then the dynamic equation for the circular movement is given by:

Fcentripetal= m*ω^2.r

q*v*B=m*ω^2.r

we write this for each particle then we have the following:

q*v*B=me* ω^2*re

q*v*B=mp* ω^2*rp

rp/re=me/mp=9.1*10^-31/1.67*10^-27=544*10^-6

4 0
3 years ago
PLEASE HELP URGETNT
Angelina_Jolie [31]

Answer:

I think (d) is right answer

6 0
3 years ago
He power output of a cyclist moving at a constant speed of 5.3 m/s on a level road is 120 w. (a) what is the force exerted on th
EleoNora [17]
P=F*V
F=P/V
F=120/5.3
F=22.6N

8 0
3 years ago
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