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kobusy [5.1K]
3 years ago
12

How does the Bohr's model of the atom differ from the quantum mechanical model?

Chemistry
1 answer:
Tom [10]3 years ago
5 0
Bohr model is valid only for hydrogen and hydrogen-like species, but quantum mechanical model can explain all elements....
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The equation, 2 H2(g) + O2(g) Imported Asset 2 H2O(l), represents an equation for a standard formation reaction.
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If this is asking if the equation is balanced, than the answer is true
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3 years ago
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3. Methyl acetate is hydrolyzed at 25 oC in acidic environment. Aliquots of equal volume are removed and titrated with NaOH solu
avanturin [10]

Solution :

Time (sec)       Volume of NaOH (mL)

339                           26.23

1242                         27.80

2745                        29.70

4546                         3.81

$\infty$                               39.81

Now the example of the first order kinetics w.r.t volumetric analysis is :

$k=\frac{2.303}{t} \log \left(\frac{v_{\infty}-v_0}{v_{\infty}- v_t}\right)$

Here, $v_{\infty}= \text{ volume at }\infty = 39.81$

$v_{t}= \text{ volume at time 't' } = 27.80$

$v_0$ = volume at time 0 = 0

Since the interval is not constant, we take the time interval as

$=\frac{903+1503+1801}{3}$

$=\frac{4207}{3}$

= 1402.3333

≈  1402 seconds

$k=\frac{2.303}{1402} \log \left(\frac{39.81-0}{39.81-27.80}\right)$

  $=(0.001643) \log \left(\frac{39.81}{10.01}\right)$

  = 0.001643 x 0.52045

  = 0.00082

  $= 8.55 \times 10^{-4} \ sec^{-1}$

Therefore, the first order rate constant is k $= 8.55 \times 10^{-4} \ sec^{-1}$.

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3 years ago
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Nataly [62]
Alkane molecule ..,x x
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3 years ago
PLEASE HELP WILL RATE THE BRAINLIEST
erastovalidia [21]

The Plum Pudding model of the atom was like a  modernchocolate chip cookie it had subatomic particles embedded inside it in no particular arrangement

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4 0
4 years ago
Will maynez burns a 0.8-g peanut beneath 76 g of water, which increases in temperature from 22âc to 46 âc. (the specific heat ca
bekas [8.4K]
Based on the information provided, it appears that you will need to calculate the amount of heat absorbed by the water from the peanut that was burned. We are given the following information:

specific heat capacity, c = 1.0 cal/g°C
mass of water = 76 g
Ti = 22°C
Tf = 46°C
change in temperature, ΔT = 24°C

We can use the formula q = mcΔT to measure the amount of energy absorbed by the water to increase in tempature:

q = (76 g)(1.0 cal/g°C)(24°C)

q = 1824 cal

Therefore, the water absorbed 1824 calories from the peanut that was burned.
7 0
4 years ago
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