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kobusy [5.1K]
2 years ago
12

How does the Bohr's model of the atom differ from the quantum mechanical model?

Chemistry
1 answer:
Tom [10]2 years ago
5 0
Bohr model is valid only for hydrogen and hydrogen-like species, but quantum mechanical model can explain all elements....
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Find the number of moles of the following substances 210 grams of NaHCO3
Triss [41]

The number of moles of 210 grams of NaHCO₃ is 2.5 moles.

<h3>How to find the Number of moles ? </h3>

To calculate the number of moles use the formula

Number of moles = \frac{\text{Given Mass}}{\text{Molar Mass}}

Mass of NaHCO₃ = 210 g

Now we have to find the Molar mass of NaHCO₃

= Atomic mass of Na + Atomic mass of H + Atomic mass of C + 3 (Atomic mass of O)

= 23 + 1 + 12 + 3 (16)

= 36 + 48

= 84 g/mol

Now put the value in above formula we get

Number of moles = \frac{\text{Given Mass}}{\text{Molar Mass}}

                             = \frac{210\ g}{84\ g/mol}

                             = 2.5 moles

Thus from the above conclusion we can say that The number of moles of 210 grams of NaHCO₃ is 2.5 moles.

Learn more about the Moles here: brainly.com/question/15356425

#SPJ1

8 0
2 years ago
Why is it difficult to clean polluted groundwater
AlekseyPX
Because the pollution will keep coming back no matter what
it can come threw the clouds and much more
8 0
3 years ago
Given the atomic radius of xenon, 1.3 ?, and knowing that a sphere has a volume of 4?r3/3, calculate the fraction of space that
34kurt
R = 1.3 A° = 1.3 × 10^(-10) m
v \:  =  \:  \frac{4}{3} \pi {r}^{3}
v \:  =  \:  \frac{4}{3}  \times 3.1415 \times  {(1.3 \times  {10}^{ - 10} )}^{3}
V = 9.20277208×10^(−30) m.
7 0
2 years ago
the lenght of the rug is 46.3 in. qnd the width is 26.3in. what is the lenght of this rug measured in centimeters
telo118 [61]
The length of the rug in cm will be
46.3 in = 117.602 cm
7 0
3 years ago
Calculate the number of moles in each of the following masses.
Agata [3.3K]

Answer:

1. 3.7 * 10^-4 mol Pd

2. 146.8 mol Fe (or 150 mol Fe if sig fig are required)

3. 52.10 g Cr

4. 14839 g Al (or 15000 g Al if sig fig are required)

5. 1.02  * 10^25 atoms Ge

Explanation:

6 0
2 years ago
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