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damaskus [11]
3 years ago
12

A jet starts at rest at the end of a runway and reaches a speed of 80 m/s in 20 s. What is its acceleration?

Physics
1 answer:
ahrayia [7]3 years ago
4 0

Answer:

Acceleration=velocity/time.

=80/2=40m/s^2.

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0.001225 kg/L x 720 000 000L =?
I am Lyosha [343]

Answer:

0.001225 kg/L × 720 000 000 L = 882000 kg

Explanation:

Given:

The equation to solve is given as:

0.001225 kg/L × 720 000 000 L = ?

Let us write each term of the product in terms of power of 10.

As 0.001225 has 6 digits after the decimal place, therefore, we use the exponent 6 for 10 and the sign is negative. This gives,

0.001225\ kg/L = 1225\times 10^{-6}\ kg/L

Now, for 720000000 L there are 6 zeros after 720. So, we use exponent 6 but with a positive sign. This gives,

720000000\ L=720\times 10^{6}\ L

Now, finding the product, we get:

0.001225\ kg/L\times 720000000\ L\\\\=1225\times 10^{-6}\ kg/L\times 720\times 10^6\ L\\\\=(1225\times 720)\times (10^6\times 10^{-6})\ (\frac{kg}{L}\times L)\\\\=882000\times 10^{6-6}\ kg\\\\=882000\times 10^0\ kg\\\\=882000\times 1\ kg\\\\=882000\ kg

Therefore, the product is equal to:

0.001225 kg/L × 720 000 000 L = 882000 kg

6 0
4 years ago
A crowbar having the length of 1.75m is used to balance a load between the fulcrum and the load is 0.5m calculate MA
aliina [53]

Answer:

1.70

Explanation:

substract 1.75-0.5

3 0
3 years ago
A spherical shell has an outside radius of 2.60 cm and an inside radius of a. The shell wall has uniform thickness and is made o
lbvjy [14]

Answer:

The answer is below

Explanation:

a) The volume of a sphere is:

Volume = (4/3)πr³; where r is the radius of the shell.

Given the outside radius of 2.60 cm and inner radius of a cm, the volume of the spherical shell is:

Volume of spherical shell = \frac{4}{3} \pi (2.6^3-a^3) cm³

But Density = mass / volume;   Mass = density * volume.

Therefore, mass of spherical shell = density * volume

mass of spherical shell = 4.70\ g/cm^3 * \frac{4}{3} \pi (2.6^3-a^3) cm³

Mass of liquid = volume of inner shell * density of liquid

Mass of liquid = \frac{4}{3} \pi a^3\ cm^3*1.23\ g/cm^3

Total mass of sphere including contents = mass of spherical shell + mass of liquid

Total mass of sphere including contents (M) = 4.70\ g/cm^3 * \frac{4}{3} \pi (2.6^3-a^3)\ cm^3  +  \frac{4}{3} \pi a^3\ cm^3*1.23\ g/cm^3 =

Total mass of sphere including contents (M) = (346 - 14.5a³) grams

b) The mass is maximum when the value of a = 0

M = 346 - 14.5a³

M' = 43.5a² = 0

43.5a² = 0

a = 0

4 0
3 years ago
A wheel is rotating about a fixed axis with constant angular acceleration 3 rad/s². At different moments, its angular speed is -
meriva

b and e are the largest and equal in magnitude. w*2R = (2)(2)R = 4R

A and d are next. aR = (3rad/s2)R = 3R

c is zero. wR = v = 0; Angular acceleration is zero.

<h3>What is angular acceleration?</h3>
  • The temporal rate at which angular velocity changes is known as angular acceleration. The standard unit of measurement is radians per second per second. Therefore, = d d t. Rotational acceleration is another name for angular acceleration.
  • Angular velocity divided by acceleration time can be used to define angular acceleration. (t). As an alternative, use pi times the drive speed (n) divided by the acceleration time (t) times 30. Radians per second squared (Rad/sec2) is the standard SI unit for rotational acceleration resulting from this equation.
  • To calculate angular velocity, we can use one of three formulas. The definition itself provides the first. Theta = position angle, t = time, and w = angular velocity, where w = angular velocity, theta = position angle, and t = time. Angular velocity is the rate of change of an object's position angle with respect to time.
  • The symbol for angular acceleration is, and it is measured in rad/s2, or radians per second square.

If two items are equal, show them as equal in your ranking. If a quantity is equal to zero, show that fact in your ranking:

b and e are the largest and equal in magnitude. w*2R = (2)(2)R = 4R

A and d are next. aR = (3rad/s2)R = 3R

c is zero. wR = v = 0; Angular acceleration is zero.

To learn more about angular acceleration, refer to:

brainly.com/question/20912191

#SPJ4

8 0
2 years ago
A pure lead bar 10 cm long is maintained with one end at T=300 K and the other at 310 K. The thermoelectric potential difference
dangina [55]

Answer:1.28v/k

Explanation:

Thermoelectric power is the same as Seebeck coefficient.

So the formula is S =Vemf/Th - Tl

= 12.8/310-300

S= 12.8/10

=1.28V/T

7 0
3 years ago
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