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lilavasa [31]
3 years ago
5

Two beams of coherent light travel different paths, arriving at point P. If the maximum destructive interference is to occur at

point P, what should be the path difference between the two waves?
The path difference between the two waves should be one and one-quarter of a wavelengths.
The path difference between the two waves should be two wavelengths.
The path difference between the two waves should be one-half of a wavelength.
The path difference between the two waves should be one wavelength.
The path difference between the two waves should be one-quarter of a wavelength.
The path difference between the two waves should be four wavelengths
Physics
1 answer:
amid [387]3 years ago
3 0
"The path difference between the two waves should be one-quarter of a wavelength" is the statement among the choices given in the question that describes the <span>path difference between the two waves. The correct option among all the options that are given in the question is the fifth statement or the penultimate statement.</span>
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How do you solve 2A= 4lw+2Lh+6wH for w
gizmo_the_mogwai [7]

Answer:

\displaystyle w=\frac{A-Lh}{2l+3H}

Explanation:

Solving Equations by Isolation

We have this equation:

2A= 4lw+2Lh+6wH

Let's solve it for w step by step. First, we flip both sides

4lw+2Lh+6wH =2A

Subtracting 2Lh in both sides

4lw+2Lh+6wH-2Lh =2A-2Lh

Simplifying

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Factoring w

w(4l+6H) =2A-2Lh

Dividing by (4l+6H)

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Simplifying by 2:

\displaystyle \boxed{w=\frac{A-Lh}{2l+3H}}

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