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schepotkina [342]
3 years ago
10

Which is an example of a chemical reaction?

Chemistry
1 answer:
allochka39001 [22]3 years ago
5 0
No it's B because of a chemical reaction between the air and iron
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If an atom has no electric charge what can be said about the number or protons and electrons it contains
valina [46]
An atom has a net zero electric charge if the number of protons and electrons it contains are the same.
8 0
3 years ago
What is the mass of disulfur pentoxide (S2O5)?
Fittoniya [83]

Answer: What is the mass of disulfur pentoxide (S2O5)?

Explanation:144.14g/mol

5 0
3 years ago
How many grams of sulfur are required in the preparation of 35.7 moles of sulfur dioxide Sg + O2 SO2​
lidiya [134]
  • S+O_2-->SO_2

Its balanced already

So

  • 1 mol SO_2 require 1 mole sulphur
  • 35.7moles require 35.7mol sulphur

Mass of S

  • 35.7(32)
  • 1142.4g
6 0
2 years ago
What can lead to being curious and also lead to fascinating scientific investigations? a. Questions b. Answers c. Qualitative Me
Ira Lisetskai [31]

Answer:

Questions

Explanation:

The word "science" was obtained from the Latin word "Scire" which means "to know". Hence science is a systematic investigation into the nature of the universe.

Scientific investigations begin with asking questions about the universe. It is this curiosity to know about occurrences in the universe as well as how to solve problems in the universe that leads to fascinating scientific investigations and discoveries.

8 0
3 years ago
The ksp of calcium carbonate, caco3, is 3.36 × 10-9 m2. calculate the solubility of this compound in g/l.
maw [93]
CaCO₃ partially dissociates in water as Ca²⁺ and CO₃²⁻. The balanced equation is,
                       CaCO₃(s) ⇄ Ca²⁺(aq) + CO₃²⁻(aq)
Initial                Y                   -                 -
Change           -X                  +X              +X
Equilibrium      Y-X                 X                X

Ksp for the CaCO₃(s) is 3.36 x 10⁻⁹ M²

                Ksp = [Ca²⁺(aq)][CO₃²⁻(aq)]
3.36 x 10⁻⁹ M² = X * X
3.36 x 10⁻⁹ M² = X²
                    X = 5.79 x 10⁻⁵ M

Hence the solubility of CaCO₃(s) = 5.79 x 10⁻⁵ M
                                                     = 5.79 x 10⁻⁵ mol/L

Molar mass of CaCO₃ = 100 g mol⁻¹

Hence the solubility of CaCO₃ = 5.79 x 10⁻⁵ mol/L x 100 g mol⁻¹
                                                 = 5.79 x 10⁻³ g/L

7 0
3 years ago
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