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3 years ago

What type of circuit will light the bulb

1 answer:

3 0

A closed circuit will light the bulb because electricity flows through it.

But on the other hand in an open circuit there is no flow of electricity current hence no light is produced

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The amount of ____ energy an object has depends on its speed and mass

andriy [413]

Kinetic energy is from speed, motion, and mass while potential energy is stored energy

8 0

3 years ago

Read 2 more answers

The work function of an element is the energy required to remove an electron from the surface of the solid. The work function fo

uranmaximum [27]

Answer:

λ = 2.38 × 10^(-7) m

Explanation:

We are given the work function for palladium as 503.7 kJ/mol.

Now let's convert this to KJ/electron.

We know from avogadro's number that;

1 mole of electron = 6.022 × 10^(23) electrons

Thus,

503.7 kJ/mol = 503.7 × 1/(6.022 × 10^(23)) = 8.364 × 10^(-22) KJ/electron = 8.364 × 10^(-19) J/electron

Formula for energy of a photon is;

E = hv

Where;

h is Planck's constant = 6.626 × 10^(-34) J.s

v is velocity

Now, v = c/λ

Where;

c is speed of light = 3 × 10^(8) m/s

λ is wavelength of light.

Thus;

E = hc/λ

Making λ the subject, we have;

λ = hc/E

λ = (6.626 × 10^(-34) × 3 × 10^(8))/(8.364 × 10^(-19))

λ = 2.38 × 10^(-7) m

4 0

2 years ago

A sample of silicon rejected for use in an electronic circuit has an impurity of boron at a level of 3 parts per trillion. What

Law Incorporation [45]

Answer:

A. 3 x 10-12

Explanation:

Generally, the parts-per notation is used to represent very small concentration without any specific unit.

Parts per million is notated as $10^{-6}$

Parts per billion is notated as $10^{-9}$

Parts per trillion is notated as $10^{-12}$

Hence, 3 parts per trillion will be written as 3 x $10^{-12}$

The correct option is A.

6 0

2 years ago

Read 2 more answers

Predict the product of this reaction <br><br> Al(s) + N2(g)—->

Rudik [331]

I attended the answer. I hope this helps you.

8 0

2 years ago

n-Butane (C4H10) is burned with stoichiometric amount of oxygen. Determine the mole fraction of carbon dioxide and water in the

Fudgin [204]

Answer:

See details below

Explanation:

The balanced reaction equation is given below:

$2C_{4} H_{10}$ + $13O_{2}$ → $8CO_{2}$ + $10H_{2} O$

Mole fraction of CO2 to H20

= 8/10 = $\frac{4}{5}$

Mole ratio of C4H10 to CO2 is 2:8 = 1:4

1 mole of n-butane - 38.12 g

4 moles - ?

= 152.48g fuel consumed.

8 0

2 years ago