What type of circuit will light the bulb

A solution has [c6h5cooh] = 0.100 m and [ca(c6h5coo)2] = 0.200 m. ka = 6.3 × 10−5 for c6h5cooh. the solution volume is 5.00 l. w

Eddi Din [679]

6.8 is the pH of the solution after 10 ml of 5M NaOH is added.

Explanation:

Data given:

Molarity of C6H5CCOH = 0.100 M

molarity of ca(c6h5coo)2 = 0.2 M

Ka = 6.3 x 10^-5

first pH is calculated of the buffer solution

pH = pKa+ log 10 $\frac{[A-]}{[HA]}$

pKa = -log10[Ka]

pka = -log[6.3 x10^-5]

pKa = 4.200

putting the values to know pH of the buffer

pH = 4.200 + log 10 $\frac{0.2}{0.1}$

pH = 4.200 + 0.3

pH = 4.5 (when NaOH was not added, this is pH of buffer solution)

now the molarity of the solution is calculated after NaOH i.e Mbuffer is added

MbufferVbuffer = Mbase Vbase

putting the values in above equation:

Mbuffer = $\frac{MbaseVbase}{Vbuffer}$

= $\frac{5X10}{5000}$

= 0.01 M

molarity or [ A-] = 5M

pH = pKa+ log 10 $\frac{[A-]}{[HA]}$

pH = 4.200 + log 10 $\frac{5}{0.01}$

pH = 4.200+ 2.69

pH = 6.8

4 0

3 years ago

Read 2 more answers

What element does this model represent?

AleksandrR [38]

Answer:

$$\tex$ Option 2: Aluminum (Al)$

Explanation:

When we are given Bohr models, we will be given a circle with rings surrounding it. The circle in the center of the model represents the nucleus, which contains the neutrons and the protons. The rings will have spherical structures that are attached to them in an orderly fashion - these model the electrons of an atom.

Protons are positively-charged subatomic particles that also identify the atom's chemical identity and atomic number. Using the number of protons, we are able to identify the element.
The neutrons are the neutrally-charged subatomic particles that give an atom its weight. When you look at a traditional periodic table, you'll see that the square that houses an element has its symbol, atomic number, and atomic mass. The atomic mass is equivalent to the sum of the protons and neutrons.
Electrons are negatively-charged subatomic particles that give an atom its overall charge. In order for an atom to be stable and neutral, the electrons must equal the protons. Otherwise, we have an unstable atom called an ion with either a positive or a negative charge. This is dependent on whether an atom has gained or lost electrons.

When we reference the model, we will see that there are 13 "p" and 14 "n" within the green circle. The "n" refers to neutrons and the "p" refers to protons. We can also count the red spheres and make quick observations about these: there are 2 red spheres on the innermost ring - for simplicity reasons, we will title this ring as r = 1. There are 8 red spheres on the middle ring - this ring will be titled r = 2. Finally, we can see that there are 2 more electrons in the outermost ring - this ring will be titled r = 3.

Now, because we have 13 protons, we know that the protons are equivalent to the atomic number.

If we check the periodic table, we will see that Silicon (Si) has an atomic number of 14. This doesn't match the number of protons, so we can rule out that a silicon atom is not the element shown.
When we use the same process and check aluminum, we discover that Aluminum (Al) has an atomic number of 13. Since the number of protons and the atomic number are equal, we can conclude that this is the element.
If we check Helium (He), we see that it has an atomic number of 2, so this is definitely not our element in question.

Now that we have concluded that Aluminum is our element, we can check this to be sure. If we use the formula m = n + p (where m is the atomic mass, n is the neutrons, and p is the protons), we can check to be sure we have selected the right element.

The given mass of aluminum on the periodic table is 26.982 atomic mass units. We round to the nearest integer when it comes to this, so we round 26.982 up to 27 even.

Now that we have determined the atomic mass and we are given the number of both protons and neutrons, we can act as if we weren't given the amount of neutrons and only the mass and amount of protons. We can then use the equation to solve for the amount of neutrons and check that the selection we made is correct.

Steps

Substitute 27 for m and 13 for p.
Subtract 13 from both sides to isolate the n and place the constants on the same side of the equation.
Combine like terms by taking the appropriate operations (in this case, this is subtracting 13 from 27).
Finally, because we are solving for n, you can reverse the equation (place the constant on the right and place the variable on the left; i.e., 72 = x → x = 72).

$27 = n + 13\\\\27 - 13 = n\\\\14 = n\\\\n = 14$

The work we just performed will allow us to confirm that because we solved for 14 neutrons, Aluminum (Al) is indeed the element represented by the model.

Hope this helps! :)

5 0

3 years ago

A man with normal lungs and an arterial PO2 of 40 mmHg takes an overdose of barbiturates that halves his alveolar ventilation wi

Colt1911 [192]

Answer:

$\frac{4}{5} = \frac{40}{x}$

Where x represent the value of interest on this case. And solving for the value of x we have:

$x = 40 * \frac{5}{4}= 50 mm Hg$

So then the new arterial pressure needs to be now 50 mm Hg to mantain the original level.

And in order to find the concentration we can use a figure called the "O2

-CO2 diagram showing a ventilation-perfusion ratio line. " and when we use this graph to calculate the pressure of Co2 for PO2= 40 mmHg and for Po2=50 mm Hg we got and increase of 0.07 or 7%

So then the final answer for this case would be an increase of 7%

Explanation:

For this case we know that a man with normal lungs have an arterial Po2 os 40 mm Hg.

Then we know that this man take an overdose of barbiturates thats halves his aveolar ventilation without changing his metabolism

We also know that the respiratory exchange ratio is 0.8 or 8/10

$0.8 = \frac{8}{10}= \frac{4}{5}$

And we want to find hor much does his inspired oxyden concentration % have to increased to return his avelolar Po2 to the original level.

On this case we can apply a proportion rule and we have this:

$\frac{4}{5} = \frac{40}{x}$

Where x represent the value of interest on this case. And solving for the value of x we have:

$x = 40 * \frac{5}{4}= 50 mm Hg$

So then the new arterial pressure needs to be now 50 mm Hg to mantain the original level.

And in order to find the concentration we can use a figure called the "O2

-CO2 diagram showing a ventilation-perfusion ratio line. " and when we use this graph to calculate the pressure of Co2 for PO2= 40 mmHg and for Po2=50 mm Hg we got and increase of 0.07 or 7%

So then the final answer for this case would be an increase of 7%

7 0

4 years ago

What is the concentration of agcl in an aqueous solution that contains 1.2 x 10-3 gram of agcl in 800. grams of the solution? 1.

Vlada [557]

Concentration can be measured in ppm. ppm means parts mer million. In terms of mass , ppm units are mg/kg.
concentration of AgCl solution is the mass of AgCl solute in mg per 1 kg of solution.
mass of AgCl present = 1.2 x 10⁻³ kg = 1.2 mg
mass of solution = 800 g = 0.800 kg
the mass of AgCl in 0.800 kg of solution = 1.2 mg
therefore mass of AgCl in 1 kg of solution = 1.2 mg / 0.800 kg x 1 kg = 1.5 mg
concentration of AgCl is 1.5 mg/kg
since mg/kg = ppm
concentration of AgCl = 1.5 ppm
answer is 1.5 ppm

3 0

4 years ago

How many atoms are in 4 Al2(SO3)3

scZoUnD [109]

There are 337.23 × 10²³ atoms in 4 moles of aluminum sulfite Al₂(SO₃)₃.

Explanation:

The questions ask how many atoms are in 4 moles of aluminum sulfite Al₂(SO₃)₃?

To answer this we use the Avogadro's number to devise the following reasoning:

if in 1 mole of Al₂(SO₃)₃ there are 14 × 6.022 × 10²³ atoms

then in 4 moles of Al₂(SO₃)₃ there are X atoms

X = (4 × 14 × 6.022 × 10²³) / 1 = 337.23 × 10²³ atoms

Learn more about:

Avogadro's number

brainly.com/question/13848085

brainly.com/question/13842198

#learnwithBrainly

4 0

3 years ago