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3 years ago

14

Help Asap, timed assignment

2 answers:

Art [367]3 years ago

7 0

Answer:

C

Explanation:

Svetllana [295]3 years ago

5 0

Answer:

Decomposers is the answer. Example of a decomposer: Mushroom

Explanation: They break down deceased organisms into the soil then that helps plants grow

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Atom , classify it<br><br><br><br><br>helppoppppoeowiie

timama [110]

Answer:

A atom is a small unit to which matter can be divided without releasing electrically charged particles

Explanation:

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2 years ago

Which of the following are part of kinetic-molecular theory? Check all that apply. The particles in a solid do not move. The par

djyliett [7]

2)The particles in a liquid are moving past one another constantly.
3)The particles in gas move freely in all directions.
4)The particles in a solid vibrate in a fixed position.
6)The particles in a gas have few attractions between them.
7)The particles in all states of matter are always moving.

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2 years ago

Read 2 more answers

The reaction 2KBr(s) →+ Br2(l) + 2K(s) is a <br>Decomposition reaction

klasskru [66]

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2 years ago

How to check atomic mass?

slavikrds [6]

Answer:

There are multiple ways to check mass but I'll tell you one. Look below

Explanation:

One easy way of checking atomic mass is by adding protons and neutrons.

For example:

We have 5 protons and 4 neutrons.

5+4=9

I hope this helps (:

8 0

3 years ago

The combustion of 1.5011.501 g of fructose, C6H12O6(s)C6H12O6(s) , in a bomb calorimeter with a heat capacity of 5.205.20 kJ/°C

avanturin [10]

Answer : The internal energy change is -2805.8 kJ/mol

Explanation :

First we have to calculate the heat gained by the calorimeter.

$q=c\times (T_{final}-T_{initial})$

where,

q = heat gained = ?

c = specific heat = $5.20kJ/^oC$

$T_{final}$ = final temperature = $27.43^oC$

$T_{initial}$ = initial temperature = $22.93^oC$

Now put all the given values in the above formula, we get:

$q=5.20kJ/^oC\times (27.43-22.93)^oC$

$q=23.4kJ$

Now we have to calculate the enthalpy change during the reaction.

$\Delta H=-\frac{q}{n}$

where,

$\Delta H$ = enthalpy change = ?

q = heat gained = 23.4 kJ

n = number of moles fructose = $\frac{\text{Mass of fructose}}{\text{Molar mass of fructose}}=\frac{1.501g}{180g/mol}=0.00834mole$

$\Delta H=-\frac{23.4kJ}{0.00834mole}=-2805.8kJ/mole$

Therefore, the enthalpy change during the reaction is -2805.8 kJ/mole

Now we have to calculate the internal energy change for the combustion of 1.501 g of fructose.

Formula used :

$\Delta H=\Delta U+\Delta n_gRT$

or,

$\Delta U=\Delta H-\Delta n_gRT$

where,

$\Delta H$ = change in enthalpy = $-2805.8kJ/mol$

$\Delta U$ = change in internal energy = ?

$\Delta n_g$ = change in moles = 0 (from the reaction)

R = gas constant = 8.314 J/mol.K

T = temperature = $27.43^oC=273+27.43=300.43K$

Now put all the given values in the above formula, we get:

$\Delta U=\Delta H-\Delta n_gRT$

$\Delta U=(-2805.8kJ/mol)-[0mol\times 8.314J/mol.K\times 300.43K$

$\Delta U=-2805.8kJ/mol-0$

$\Delta U=-2805.8kJ/mol$

Therefore, the internal energy change is -2805.8 kJ/mol

5 0

2 years ago