Hi Student,
Soory for not answer there but I needed help from someone , can you inbox me please !!
I am a Indian and I come there for seeing education system in your country. please, can you provide me some help ?
My Account name is jaiveersingh70 in Indian server of brainly. you can check my identity.
if you have not inbox power, So tell your friend about me and ask for inbox.
Thank You :)
Ex - Stars Team
jaiveersingh70
Atp is a form of energy and it is generated through a chemical process called substrate level phosphorylation.
<h3 /><h3>What is substrate level phosphorylation?</h3>
Substrate-level phosphorylation is a reaction that makes use of substrate to generate Adenosine triphosphate (ATP) which is a form of energy.
ATP is produced through the transfer of phosphate group from the substrate directly to adenosine diphosphate (ADP).
Therefore, substrate-level phosphorylation generates the atp produced in glycolysis.
Learn more on substrate level phosphorylation here,
brainly.com/question/7331523
1) Chemical reaction: 2Al + 3Br₂ → 2AlBr₃.
m(Al) = 3,0 g.
m(Br₂) = 6,0 g.
n(Al) = m(Al) ÷ M(Al).
n(Al) = 3,0 g ÷ 27 g/mol.
n(Al) = 0,11 mol.
n(Br₂) = n(Br₂) ÷ m(Br₂).
n(Br₂) = 6 g ÷ 160 g/mol.
n(Br₂) = 0,0375 mol; limiting reagens.
n(Br₂) : n(AlBr₃) = 3 : 2.
n(AlBr₃) = 0,025 mol.
m(AlBr₃) = 0,025 mol · 266,7 g/mol.
m(AlBr₃) = 6,67 g.
2) m(Br₂) - all bromine reacts, so mass of bromine after reaction is zero grams (m(Br₂) = 0 g).
n(Al) = 0,11 mol - 0,025 mol = 0,085 mol.
m(Al) = 0,085 mol · 27 g/mol.
m(Al) = 2,295 g.
m(AlBr₃) = 6,67 g · 0,72 (yield of reaction).
m(AlBr₃) = 4,8 g.
n - amount of substance.
M - molar mass.
The answer is gonna be D I believe