1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
kakasveta [241]
2 years ago
5

A current carrying wire of length 50cm is positioned perpendicular to a uniform magnetic field

Physics
1 answer:
RideAnS [48]2 years ago
3 0

A current-carrying wire of length 50 cm is positioned perpendicular to a uniform magnetic field. The magnetic field strength is 0.6 Tesla.

<h3>What is magnetic field?</h3>

The magnetic field is the region of space where an object experiences a magnetic force as it enters the field.

Given is the wire of length 50 cm = 0.5 m and the current is 10.0 A. There is a resultant force of 3.0 N on the wire due to the interaction of the current and field.

The relation between magnetic field strength and current is

F = ILB

Substituting 50 for L, 10 for I and 3 for F, we get the magnetic field strength B.

3 = 10 × 0.5 × B

B= 0.6 Tesla

Therefore, the magnetic field strength is 0.6 Tesla.

Learn more about magnetic field.

#SPJ

You might be interested in
A 60.0 kg soccer player kicks a 0.4000 kg stationary soccer ball with 6.25 N of force. How fast does the soccer ball accelerate,
frozen [14]
F = ma
6.25 N = 0.4 kg · a
a = (6.25/0.4) m/s²      since N=kg·m/s²
a = 15.625 m/s² 

The answer is c) 15.6 m/s²
(Note that the mass of the soccer player is irrelevant.)
8 0
3 years ago
A car is traveling at 16 m/s^2
Leya [2.2K]
Really? wow that's pretty cool
4 0
3 years ago
How much force is required to move a electron through an electric field with strength of 1.375 x 10^19 N/C?
Luda [366]

Answer:

The magnitude of the force required to move the electron through the given field is 2.203 N

Explanation:

Given;

The field strength of the electron, E = 1.375  x 10¹⁹ N/C

charge of electron, q = 1.602 x 10⁻¹⁹ C

The magnitude of the force required to move the electron through the given field is calculated as follows;

F = Eq

F = (1.375  x 10¹⁹ N/C) (1.602 x 10⁻¹⁹ C)

F = 2.203 N

Therefore, the magnitude of the force required to move the electron through the given field is 2.203 N

4 0
3 years ago
A vertical spring gun is used to launch balls into the air. If the spring is compressed by 4.9 cm, the ball of mass 5.5 g is lau
AleksandrR [38]

We know, by conservation of energy :

\dfrac{kx^2}{2}=mgh

Therefore,

\dfrac{x_1^2}{x_2^2}=\dfrac{h_1}{h_2}

Putting given values, we get :

\dfrac{x_1^2}{x_2^2}=\dfrac{h_1}{h_2}\\\\\dfrac{4.9^2}{x_2^2}=\dfrac{50.2}{2\times 50.2}\\\\x_2^2=2\times 4.9^2\\\\x_2 = 4.9\times \sqrt{2}\\\\x_2=6.93\ cm

Therefore, the spring be compressed to 6.93 cm to send the ball twice as high.

Hence, this is the required solution.

6 0
3 years ago
What did copernicus say about the motion of the sun?.
eimsori [14]

the sun was stationary in the center of the universe and the earth revolved around it....

8 0
2 years ago
Other questions:
  • A car weighing 15,000 n is speeding down the highway at 90 km/h. what is its momentum?
    11·2 answers
  • A hypothetical spherical planet consists entirely of iron. what is the period of a satellite that orbits this planet just above
    15·1 answer
  • What property do the following elements have in common? sulfur, iodine, and magnesium A) Same phase at room temperature. B) Good
    10·2 answers
  • Which scientist proposed the idea of a sun-centered solar system instead of an earth-centered solar system?
    14·1 answer
  • A car has positive acceleration. What information can you infer from this? A- The car is changing direction. B- The car is speed
    6·2 answers
  • If you lived in Syracuse, you may have experienced _____.
    10·1 answer
  • You are leaving for a party at your cousin’s house in a city that is 150 km away. You will travel at an average rate of 50 km/hr
    12·2 answers
  • A 75.0 kg stunt man jumps from a balcony and falls 24.0
    10·1 answer
  • How did Robert Whittaker change classification?
    12·2 answers
  • Help me <img src="https://tex.z-dn.net/?f=%5Chuge%5Cmathcal%5Cred%7B%7D" id="TexFormula1" title="\huge\mathcal\red{}" alt="\huge
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!