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kakasveta [241]
2 years ago
5

A current carrying wire of length 50cm is positioned perpendicular to a uniform magnetic field

Physics
1 answer:
RideAnS [48]2 years ago
3 0

A current-carrying wire of length 50 cm is positioned perpendicular to a uniform magnetic field. The magnetic field strength is 0.6 Tesla.

<h3>What is magnetic field?</h3>

The magnetic field is the region of space where an object experiences a magnetic force as it enters the field.

Given is the wire of length 50 cm = 0.5 m and the current is 10.0 A. There is a resultant force of 3.0 N on the wire due to the interaction of the current and field.

The relation between magnetic field strength and current is

F = ILB

Substituting 50 for L, 10 for I and 3 for F, we get the magnetic field strength B.

3 = 10 × 0.5 × B

B= 0.6 Tesla

Therefore, the magnetic field strength is 0.6 Tesla.

Learn more about magnetic field.

#SPJ

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Answer:A converging lens is thickest in the middle and causes parallel light rays to converge through the focal point on the opposite side of the lens. A diverging lens is thinner in the middle and causes parallel light rays to diverge away from the focal point on the same side of the lens.

Explanation:

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A commuter backs her car out of her garage with an acceleration of 1.40 m/s^2. (a) How long does it take her to reach a speed of
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Answer:

a) It takes her 1.43 s to reach a speed of 2.00 m/s.

b) Her deceleration is - 2.50 m/s²

Explanation:

The equation of velocity for an object that moves in a straight line with constant acceleration is as follows:

v = v0 + a · t

Where:

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t = time.

a) Using the equation of velocity, let´s consider that the car moves in the positive direction. Then:

v = v0 + a · t

2.00 m/s = 0 m/s + 1.40 m/s² · t

t = 2.00 m/s / 1.40 m/s²

t = 1.43 s

It takes her 1.43 s to reach a speed of 2.00 m/s

b) Let´s use again the equation of velocity, knowing that at t = 0.800 s the velocity is 0 m/s:

v = v0 + a · t

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Answer:

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