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kakasveta [241]
2 years ago
5

A current carrying wire of length 50cm is positioned perpendicular to a uniform magnetic field

Physics
1 answer:
RideAnS [48]2 years ago
3 0

A current-carrying wire of length 50 cm is positioned perpendicular to a uniform magnetic field. The magnetic field strength is 0.6 Tesla.

<h3>What is magnetic field?</h3>

The magnetic field is the region of space where an object experiences a magnetic force as it enters the field.

Given is the wire of length 50 cm = 0.5 m and the current is 10.0 A. There is a resultant force of 3.0 N on the wire due to the interaction of the current and field.

The relation between magnetic field strength and current is

F = ILB

Substituting 50 for L, 10 for I and 3 for F, we get the magnetic field strength B.

3 = 10 × 0.5 × B

B= 0.6 Tesla

Therefore, the magnetic field strength is 0.6 Tesla.

Learn more about magnetic field.

#SPJ

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Suppose two children push horizontally, but in exactly opposite directions, on a third child in a wagon. The first child exerts
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(a) The system of interest if the acceleration of the child in the wagon is to be calculated are the wagon and the children outside the wagon.

(b) The acceleration of the child-wagon system is 0.33 m/s².

(c) Acceleration of the child-wagon system is zero when the frictional force is 21 N.

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∑F = ma

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∑F = 96 N - 75 N - 12 N = 9 N

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<h3>Free body diagram</h3>

           →                 →              Ф                         ←

         1st child      friction       wagon                2nd child

<h3>Acceleration of the  child and wagon system</h3>

a = ∑F/m

a = 9 N / 27 kg

a = 0.33 m/s²

<h3>When the frictional force is 21 N</h3>

∑F = 96 N - 75 N - 21 N = 0 N

a = ∑F/m

a = 0/27 kg

a = 0 m/s²

Learn more about net force here: brainly.com/question/14361879

#SPJ1

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