The balanced equation above will be; 2 KClO3 = 2 KCl + 3 O2 Therefore, the coefficients are; 2,2,3 Which means 2 KClO3 will create 2 KCl and 3 oxygen molecules.
From the balanced equation 2KClO3 → 2KCl + 3O2, the coefficients are the following: coefficient 2 in front of potassium chlorate KClO3 coefficient 2 in front of potassium chloride KCl coefficient 3 in front of oxygen molecule O2
We got this balanced equation by identifying the number of atoms of each element that we have in the given equation KClO3 → KCl + O2. Looking at the subscripts of each atom on the reactant side and on the product side, we have KClO3 → KCl + O2 K=1 K=1 Cl=1 Cl=1 O=3 O=2
We can see that the oxygens are not balanced. We add a coefficient 2 to the 3 oxygen atoms on the left side and another coefficient 3 to the 2 oxygen atoms on the right side to balance the oxygens: 2KClO3 → KCl + 3O2 The coefficient 2 in front of potassium chlorate KClO3 multiplied by the subscript 3 of the oxygen atoms on the left side indicates 6 oxygen atoms just as the coefficient 3 multiplied by the subscript 2 on the right side indicates 6 oxygen atoms.
The number of potassium K atoms and chloride Cl atoms have changed as well: 2KClO3 → KCl + 3O2 K=2 K=1 Cl=2 Cl=1 O=6 O=6
We now have two potassium K atoms and two chloride Cl atoms on the reactant side, so we add a coefficient 2 to the potassium chloride KCl on the product side: 2KClO3 → 2KCl + 3O2, which is our final balanced equation. K=2 K=2 Cl=2 Cl=2 O=6 O=6 The potassium, chlorine, and oxygen atoms are now balanced.
