Answer:
- Dalton used creativity to modify Proust's experiment and interpret the results.
- Thomson used creativity to interpret the results of the cathode ray tube experiment.
Explanation:
give me brainlest
pH=2.7
<h3>Further explanation</h3>
Acetic acid = weak acid
![\tt [H^+]=\sqrt{Ka.M}](https://tex.z-dn.net/?f=%5Ctt%20%5BH%5E%2B%5D%3D%5Csqrt%7BKa.M%7D)
Ka = acid ionization constant
M = molarity
Ka for Acetic acid(CH₃COOH) : 1.8 x 10⁻⁵
![\tt [H^+]=\sqrt{1.8\times 10^{-5}\times 0.222}\\\\=0.001998=1.998\times 10^{-3}](https://tex.z-dn.net/?f=%5Ctt%20%5BH%5E%2B%5D%3D%5Csqrt%7B1.8%5Ctimes%2010%5E%7B-5%7D%5Ctimes%200.222%7D%5C%5C%5C%5C%3D0.001998%3D1.998%5Ctimes%2010%5E%7B-3%7D)

Substances that are less dense than water will FLOAT and substances with a density that is greater than 1.00g/ml will SINK.
Answer:
E = 12.92 × 10^(-16) J
Explanation:
Formula for energy is;
E = hc/λ
Where;
h is Planck's constant = 6.63 x 10^(-34) J.s
c is speed of light = 3 × 10^(8) m/s
λ is wavelength = 0.154 nm = 0.154 × 10^(-9) m
E = (6.63 x 10^(-34) × 3 × 10^(8))/(0.154 × 10^(-9))
E = 12.92 × 10^(-16) J
Answer:
Hydrogen ion concentration is 2.773E-4Mole per DM3
Hydroxide ion concentration is 4.093E-11
It is an acid
Explanation:
PH(H3O)=-LogH3O
PH=3.557
H3O=antilog of -3.557
antilog of -3.557=antilog (0.443 -4)
antilog0.443 ×antilog -4=2.773E-4mole per DM3.
(H3O)(OH)=10^-14
H30=2.773×10^-14
OH= 1.00E-14/2.773E-4
=4.093E-11
it is an acid since the concentration of hydrogen ion is more than the hydroxide ion