A student conducted an experiment to measure the acceleration due to gravity 'g' of a simple pendulum.

1 point

s2008m [1.1K]

Answer:

The person has no displacement

Explanation:

The given parameters are

The location of the person = The equator

The distance covered in one revolution = Total distance around the body

The total distance around the Earth = The circumference of the Earth = 40.075 kilometres

The total distance moved by the person standing at the equator during the Earths complete revolution = 40,075 kilometres

The initial location of the person in relation to a fixed point in space outside Earth at the start of the revolution = x km

The final location of the person in relation to the fixed point in space outside Earth at the completion of the revolution = x km

The displacement = Change in position = Final location - Initial location

∴ The displacement = x km - x km = 0 km.

5 0

4 years ago

If 6000 J of heat is added to 200 gm of water at 25° C. What will be its final<br>temperature?

Debora [2.8K]

Answer:

T₂ = 305.17 K

Explanation:

Given that,

Heat, Q = 6000 J

Mass, m = 200 gram

Initial temperature, T₁ = 25° C

We need to find its final temperature. Let it is T₂.

We know that,

$Q=mc\Delta T$

Where

c is the specific heat of water, c = 4.18 J/g°C

So,

$6000=200\times 4.18\times (T_2-298)\\\\\dfrac{6000}{200\times 4.18}=(T_2-298)\\\\7.17=(T_2-298)\\\\7.17+298=T_2\\\\T_2=305.17\ K$

So, the final temperature is equal to 305.17 K.

3 0

3 years ago

In a certain physics experiment, carts run along a frictionless, level track. Cart A is 1 kg and Cart B is 2 kg. Initially cart

timofeeve [1]

Answer: $v=-\frac{11}{3} m/s \left$

Explanation:

Given

Mass of car A $\left ( m_a\right )=1 kg$

Mass of car B $\left ( m_b\right )=2 kg$

velocity of cart A=3 m/s

velocity of cart B=-7 m/s

Conserving momentum

$m_au_a+m_bu_b=\left ( m_a+m_b\right )v$

$v=\frac{m_au_a+m_bu_b}{\left ( m_a+m_b\right )}$

$v=-\frac{11}{3} m/s \left ( i.e. in\ left\right )$

6 0

3 years ago

These UV photons can break chemical bonds in your skin to cause sunburn—a form of radiation damage. If the 305 nm radiation prov

astraxan [27]

Answer:

energy = 391.902 kJ /mol

Explanation:

given data

wavelength = 305 nm = 305 × $10^{-9}$ m

to find out

average energy

solution

we know speed of light is 3 × $10^{8}$ m/s

so we find frequency here first by speed of light formyla

speed = wavelength × frequency

3 × $10^{8}$ = 305 × $10^{-9}$ × frequency

frequency = 9.8360 × $10^{14}$ $s^{-1}$

so energy is

energy = hf

here h = 6.62 × $10^{-34}$ J-s

so

energy = 6.62 × $10^{-34}$ × 9.8360 × $10^{14}$

energy = 6.51 × $10^{-14}$ J

so

energy = 6.51 × $10^{-14}$ × $\frac{6.02*10^23}{1000}$ kJ/mol

energy = 391.902 kJ /mol

7 0

4 years ago

Despite a very strong wind, a tennis player

Gnoma [55]

Answer:

Option 5. 1 and 3

Solution:

The only forces acting on the tennis ball after it has left contact with the racquet and the instant before it touches the ground are the force of gravity in the downward direction and the force by the air exerted on the ball.

The ball after it left follows the path of trajectory and as it moves forward in the horizontal direction the force of the air acts on it.

In the whole projectile motion of the ball, the acceleration due to gravity acts on the ball thus the force of gravity acts on the ball in the downward direction before it hits the ground.

6 0

4 years ago