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zalisa [80]
3 years ago
9

What are the three different types of muscle tissue?

Physics
1 answer:
Novosadov [1.4K]3 years ago
8 0

Answer:

skeletal,cardiac,and smooth.

Explanation:

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Briefly describe factors and characteristics that influence conflict resolution.
Reptile [31]

Answer:

Personal attitudes play a role in conflict resolution and include prejudices, biases, prior experience, and the level of importance of a topic to the parties involved. It is important to note that you can control your own attitude, but you cannot control the attitudes of others; it is necessary to focus on your attitudes and assumptions before you address the other party's. Next, you need to know what the nature of the conflict is, or what the conflict is about. It is necessary to know how severe the conflict is, how easily it can be resolved, how much sacrifice it will take to overcome, and how heated it is likely to get. Lastly, one needs to understand the capabilities of the people involved. Is everyone on the same level and do they have what they need to work on the conflict, i.e. money, time, and support?

Explanation:

7 0
3 years ago
Read 2 more answers
Listening to your favorite radio station involves which area of physics?
lukranit [14]

If I'm not mistaken the answer would be c, vibrations and wave phenomena, because when sound waves hit your ear they go through it to your brain and your mind translates these vibrations to sound. I hope my answer helped you out.

8 0
3 years ago
A cannon sends a projectile towards a target a distance 1420 m away. The initial velocity makes an angle 35◦ with the horizontal
ss7ja [257]

Answer:

v_{o}=141.51m/s

Explanation:

From the exercise we know the final x distance, the angle which the projectile is being released and acceleration of gravity

x=1420m\\g=-9.8m/s^{2}

From the equation of x-position we know that

x=v_{ox}t=v_{o}cos(35)t

Solving for v_{o}

v_{o}=\frac{x}{tcos(35)} =\frac{1420m}{tcos(35)} (1)

Now, if we analyze the equation of y-position we got

y=y_{o}+v_{oy}t+\frac{1}{2}gt^{2}

At the end of the motion y=0

0=v_{o}sin(35)t+\frac{1}{2}gt^{2}

Knowing the equation for v_{o} in (1)

0=\frac{1420}{tcos(35)}tsin(35)-\frac{1}{2}(9.8)t^{2}

\frac{1}{2}(9.8)t^{2}=1420tan(35)

Solving for t

t=\sqrt{\frac{2(1420tan(35))}{9.8} } =14.25s

Now, we can solve (1)

v_{o}=\frac{1420m}{(14.25s)cos(35)}=141.51m/s

6 0
3 years ago
Read 2 more answers
5. Find the mass of a car that is traveling at a velocity of 35 m/s West.
sattari [20]

Answer:

m = 9795.9 kg

Explanation:

v = 35 m/s

KE = 6,000,000 J

Plug those values into the following equation:

KE = \frac{1}{2} mv^{2}

6,000,000 J = (1/2)(35^2)m

---> m = 9795.9 kg

3 0
3 years ago
Plz hurry How fast can work be done by a 7 horsepower engine?
den301095 [7]

Answer:

It will go about 45-50 mph.

Explanation:

Depending on what you are hauling.

7 0
3 years ago
Read 2 more answers
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