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3 years ago

7

Sketch the solid whose volume is given by the integral and evaluate the integral. $ \int_{0}^{{\color{red}6}}\int_{0}^{2\pi }\in

t_{{\color{red}4} r}^{{\color{red}24}}\,r\,dz\,d\theta \,dr

1 answer:

Serggg [28]3 years ago

8 0

Answer:

Explanation:

Attached is the evaluation

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What is the net force on a 50-newton weight hanging on a string tied to the ceiling?

Lady bird [3.3K]

The net force on the hanging object is zero. If it were not zero, then the object would be accelerating in some direction.

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3 years ago

A car interior is heated to 48 C by the sun What type of energy transfer?

Aneli [31]

Answer:

Radiation heat energy transfer

Explanation:

The type of heat transfer from the Sun is radiation heat transfer, which is the transfer of heat through electromagnetic radiation

The distance of the Sun to the Earth is several million kilometers away, with the space between being composes of vacuum and the nuclear reaction in the Sun's core generates vast amount of electromagnetic radiation that is transferred all across the universe and reaches the Earth as visible light and radiant energy at the speed of light

The radiant energy transferred from the Sun heats up the Earth, including the car's interior.

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3 years ago

. A 2.0-kg block is on a perfectly smooth ramp that makes an angle of 30° with the horizontal. (a) What is the block’s accelerat

AfilCa [17]

Answer:

a) a = 4.9 m / s², N = 16.97 N and b) F = 9.8 N

Explanation:

a) For this exercise we will use Newton's second law, we write a reference system with the x axis parallel to the plane, see attached, in this system the only force we have to break down is weight, let's use trigonometry

sin 30 = Wx / W

cos 30 = Wy / W

Wx = W sin30

Wy = W cos 30

Let's write the equations on each axis

X axis

Wx = ma

Y Axis

N- Wy = 0

N = Wy = mg cos 30

N = 2.0 9.8 cos 30

N = 16.97 N

We calculate the acceleration

a = Wx / m

a = mg sin 30 / m

a = g sin 30

a =9.8 sin 30

a = 4.9 m / s²

b) For the block to move with constant speed, the acceleration must be zero, so the force applied must be equal to the weight component

F -Wx = 0

F = Wx

F = m g sin 30

F = 2.0 9.8 sin 30

F = 9.8 N

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3 years ago

Water enters a baseboard radiator at 180 °F and at a flow rate of 2.0 gpm. Assuming the radiator releases heat into the room at

beks73 [17]

Answer:

Temperature of water leaving the radiator = 160°F

Explanation:

Heat released = (ṁcΔT)

Heat released = 20000 btu/hr = 5861.42 W

ṁ = mass flowrate = density × volumetric flow rate

Volumetric flowrate = 2 gallons/min = 0.000126 m³/s; density of water = 1000 kg/m³

ṁ = 1000 × 0.000126 = 0.126 kg/s

c = specific heat capacity for water = 4200 J/kg.K

H = ṁcΔT = 5861.42

ΔT = 5861.42/(0.126 × 4200) = 11.08 K = 11.08°C

And in change in temperature terms,

10°C= 18°F

11.08°C = 11.08 × 18/10 = 20°F

ΔT = T₁ - T₂

20 = 180 - T₂

T₂ = 160°F

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3 years ago

4. Two particles, A and B, are in uniform circular motion about a common center. The acceleration of particle A is 7.3 times tha

HACTEHA [7]

Answer:

Explanation:

Acceleration of particle A is 7.3 times the acceleration of particle B.

Let the acceleration of particle B is a, then the acceleration of particle A is

7.3 a.

Let the period of particle A is T and the period of particle B is 2.5 T.

Let the radius of particle A is RA and the radius of particle B is RB.

Use the formula for the centripetal force

$a=r\omega ^{2}=r\times \frac{4\pi^{2}}{T^{2}}$

So, $r = a\frac{T^{2}}{4\pi^{2}}$

The ratio of radius of A to the radius of B is given by

$\frac{R_{A}}{R_{B}}=\frac{a_{A}\times T_{A}^{2}}{a_{B}\times T_{B}^{2}}$

$\frac{R_{A}}{R_{B}}=\frac{7.3 a\times T^{2}}{a\times 6.25T^{2}}$

RA : RB = 1.17

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3 years ago

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