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Drupady [299]
3 years ago
8

Join not for bâd purpose​

Physics
2 answers:
Alex_Xolod [135]3 years ago
4 0

Suspicious?

Why ask for random people to join?

saw5 [17]3 years ago
3 0

Explanation:

zoom I'd - 9038735228 pwd -97cEeT I m getting bored wanna come for intresting talk

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The qualitative equivalent of external validity is:
Setler79 [48]
C transformability i think
7 0
3 years ago
Why do quarterbacks throw the football with significant spin about its long axis?
Lera25 [3.4K]

(a) the principle of aerodynamic convergence

(b) the centripetal force

(c) Conservation of angular momentum

(d) Conservation of kinetic energy

(e) None of these

Conservation of angular momentum

Answer: Option C.

<u>Explanation:</u>

The law of conservation of angular momentum expresses that when no outer torque follows up on an article, no difference in precise force will happen.

The law of conservation of angular momentum expresses that the angular energy of a body that is the result of its snapshot of latency about the hub of revolution and its rakish speed about a similar pivot, can't change except if an outside torque follows up on the framework.

7 0
4 years ago
A skier with a 65kg mass skies down a 30 degree incline hill. The coefficient of friction is 0.1. a. Draw a free body diagram. b
djyliett [7]
B is the answer! Because no one would be pushing the rock all the way down the hill it would just go down by itself by rolling!!



Hope i helped plz mark as brainlist and 5 star'!
6 0
4 years ago
A cylindrical tank has a radius of 53 cm and a height of 1200 mm. It weighs 9.6 kN
xxTIMURxx [149]

Answer:

1985kg

Explanation:

assuming that

pi =3.14

oil density = 950kg/ cubic meter

g= 9.8m/s

M=\frac{9600}{9.8 } + 950 * 3.14*.53^{2} *1.2=1985kg

4 0
3 years ago
a 230 kg roller coaster reaches the top of the steepest hill with a speed of 6.2 km/h. It then descends the hill, which is at an
igor_vitrenko [27]

Answer: 81.619 kJ

Explanation:

Given

Mass of roller coaster is m=230\ kg

It reaches the steepest hill with speed of u=6.2\ km/h\ or \ 1.72\ m/s

Hill to bottom is 51 m long with inclination of 45^{\circ}

Height of the hill is h=51\sin 45^{\circ}=36.06\ m

Conserving energy to get kinetic energy at bottom

Energy at top=Energy at bottom

\Rightarrow K_t+U_t=K_b+U_b\\\Rightarrow \dfrac{1}{2}mu^2+mgh=K_b+0\\\\\Rightarrow K_b=0.5\times 230\times 1.72^2+230\times 9.8\times 36.06\\\Rightarrow K_b=340.216+81,279.24\\\Rightarrow K_b=81,619.456\ J\\\Rightarrow K_b=81.619\ kJ

8 0
3 years ago
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