What is the total current in a parallel circuit containing a 12-V battery, a 2 Ω resistor, and a 4 Ω resistor?
1 answer:
Answer:
V=IR
since the circuit is parallel both resistor have same voltage and different current value according to OHMs law.
total resistance in parallel=
1/R=1/R1+1/R2+...+1/Rn
since we have two resistor in parallel
Rt=R1R2/R1+R2
2*4/2+4=4/3 ohms
I=V/R
12/4/3=36/4=9Amp
OR
I=12/2=6amp
I=12/4=3amp
total current
I=6+3
9amp
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