All categories

3 years ago

What is the total current in a parallel circuit containing a 12-V battery, a 2 Ω resistor, and a 4 Ω resistor?

Physics

1 answer:

deff fn [24]3 years ago

7 0

Answer:

V=IR

since the circuit is parallel both resistor have same voltage and different current value according to OHMs law.

total resistance in parallel=

1/R=1/R1+1/R2+...+1/Rn

since we have two resistor in parallel

Rt=R1R2/R1+R2

2*4/2+4=4/3 ohms

I=V/R

12/4/3=36/4=9Amp

I=12/2=6amp

I=12/4=3amp

total current

I=6+3

9amp

You might be interested in

The A note has a frequency of 440 Hz. What is the wavelength if the speed of sound is 343 m/s?

Nina [5.8K]

The wavelength of a wave (λ) is given by λ $= \frac{c}{f}$
where c is the wave speed and f is the frequency

7 0

3 years ago

Read 2 more answers

Why must the electric field be normal to the surface at every point of a charged conductor?

solong [7]

-- If the field were inclined to the surface, then it would have
some component parallel to the surface.

-- Then, since we're talking about a conductor, the charges
on the object would move in response to that component
of the field, until there was no longer any component of the
field trying to move them.

3 0

3 years ago

A rectangular coil of 65 turns, dimensions 0.100 m by 0.200 m, and total resistance 10.0 ? rotates with angular speed 29.5 rad/s

vovikov84 [41]

Answer:

Explanation:

N = 65

Area, A = 0.1 x 0.2 = 0.02 m^2

R = 10 ohm

ω = 29.5 rad/s

B = 1 T

(a) at t = 0

e = N x B x A x ω

e = 65 x 1 x 0.02 x 29.5

e = 38.35 V

(b) The maximum rate of change of magnetic flux is equal to the maximum value of induced emf.

Ф = 38.35 Wb/s

e = 65 x 1 x 0.02 x 29.5 x Sin (29.5 x 0.05)

e = 38.174 V

(d) Maximum torque

τ = M B Sin 90

τ = N i A B

τ = N e A B / R

τ = 65 x 38.35 x 0.02 x 1 / 10

τ = 5 Nm

8 0

3 years ago

A certain parallel-plate capacitor is filled with a dielectric for which κ = 6.56. The area of each plate is 0.0830 m2, and the

mafiozo [28]

Answer:

$4.86\times 10^{-7}\ J$

Explanation:

Given:

Dielectric of the medium between the plates (k) = 6.56

Area of eac plate (A) = 0.0830 m²

Separation between the plates (d) = 1.95 mm = 0.00195 m [1 mm = 0.001 m]

Maximum electric field $(E_{max})$ = 202 kN/C = 202000 N/C [1 kN = 1000 N]

Permittivity of space (ε₀) = 8.854 × 10⁻¹² F/m

The maximum potential difference across the plates of the capacitor is given as:

$V_{max}=E_{max}d\\\\V=(202000\ N/C)(0.00195\ m)\\\\V=393.9\ V$

Now, capacitance of the capacitor is given as:

$C=\dfrac{k\epsilon_0A}{d}\\\\C=\frac{6.56\times 8.854\times 10^{-12}\ F/m\times 0.0830\ m^2}{0.00195\ m}\\\\C=2.47\times 10^{-9}\ F$

The maximum energy stored in the capacitor is given as:

$U_{max}=\frac{1}{2}CV_{max}^2\\\\U_{max}=\frac{1}{2}\times (2.47\times 10^{-9}\ F)\times 393.9\ V\\\\U_{max}=4.86\times 10^{-7}\ J$

Therefore, the maximum energy that can be stored in the capacitor is $4.86\times 10^{-7}\ J$

6 0

3 years ago

Calculate the time (in seconds) needed for a car to accelerating from 0 m/s to 10 m/s at 5 m/s^2?

bazaltina [42]

Answer: 2 s

Explanation: In order to solve this problem we have to use the formule of the final speed getting with a constant acceleration, it is given by;

Vfinal=Vo+a*t where Vo is zero.

so then t=Vfinal/a = (10 m/s)/5 m/s^2= 2 s

4 0

3 years ago