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3 years ago

What is the total current in a parallel circuit containing a 12-V battery, a 2 Ω resistor, and a 4 Ω resistor?

Physics

1 answer:

deff fn [24]3 years ago

7 0

Answer:

V=IR

since the circuit is parallel both resistor have same voltage and different current value according to OHMs law.

total resistance in parallel=

1/R=1/R1+1/R2+...+1/Rn

since we have two resistor in parallel

Rt=R1R2/R1+R2

2*4/2+4=4/3 ohms

I=V/R

12/4/3=36/4=9Amp

I=12/2=6amp

I=12/4=3amp

total current

I=6+3

9amp

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2 years ago

You throw a ball with a mass of 0.50 kg against a brick wall. It hits the wall moving horizontally to the left at 20 m/s and reb

Orlov [11]

Answer:

The value of impulse of the net force on the ball during its collision with wall is $I = 15\ kg \frac{m}{s}$

The value of average horizontal force that the wall exerts on the ball during the impact is F = 15000 N

Explanation:

Mass of the ball = 0.5 kg

Horizontal velocity $V_{x}$ = 20 $\frac{m}{s}$

Velocity after collision $V_{-x}$ = - 10 $\frac{m}{s}$

(A). Impulse of the net force on the ball during its collision with wall is

$I = m (V_{x} - V_{-x})$

I = 0.5 × (20 + 10)

$I = 15\ kg \frac{m}{s}$

This is the value of impulse of the net force on the ball during its collision with wall.

(B). The magnitude of average horizontal force

$F = \frac{I}{T}$

Where F = Force

I = impulse & t = time interval = 0.001 sec

$F = \frac{15}{0.001}$

F = 15000 N

This is the value of average horizontal force that the wall exerts on the ball during the impact.

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3 years ago

Monochromatic light of wavelength 720 nm is incident on parallel slits, of width 0.420 mm, separated by 0.560 mm. A diffraction

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Answer:

1.81×10^-4Io

Explanation:

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4 years ago

Which would be the most reliable source of information to use for a history report

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A textbook but if there none to good use try google

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3 years ago

Liquid flows through a 4.0 cm diameter pipe at 1.0 m/s. there is a 2.0 cm diameter restriction on the line. what is the velocity

Vanyuwa [196]

To determine the velocity in the restriction, we need to remember the law of conservation of mass where mass in should be equal to the mass out since mass cannot be created or destroyed. For this system, mass flow rate in is equal to mass flow rate out. We do as follows:

Mass flow rate in = Mass flow rate out
density (volumetric flow rate in) = density (volumetric flow rate out)

Since the liquid in and out are the same, then density would be cancelled.
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3 years ago