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Irina-Kira [14]
3 years ago
12

Two parallel plates 19 cm on a side are given equal and opposite charges of magnitude 2.0 ✕ 10^−9 C. The plates are 1.8 mm apart

. What is the electric field (in N/C) at the center of the region between the plates? (Enter the magnitude.)
Physics
1 answer:
Romashka [77]3 years ago
5 0

Answer:

E   = 5291.00 N/C

Explanation:

Expression for capacitance is

C = \frac{\epsilon  A}{d}

where

A is area of square plate

D = DISTANCE BETWEEN THE PLATE

C = \frac{\epsilon\times(19\times 10^{-2})^2}{1.5\times 10^{-3}}

C = 24.06 \epsilon

C = 24.06\times 8.854\times 10^{-12} F

C =2.1\times 10^{-10} F

We know that capacitrnce and charge is related as

V = \frac{Q}{C}

 = \frac{2\tiimes 10^{-9}}{2.\times 10^{-10}}

v = 9.523 V

Electric field is given as

E = \frac{V}{d}

   = \frac{9.52}{1.8*10^{-3}}

E   = 5291.00 V/m

E   = 5291.00 N/C

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1. While John is traveling along an interstate highway, he notices a 160-mile marker as he passes through town. Later John passe
pogonyaev

Number of miles that marker shows when passes through town= 160 miles.

Number of miles that marker shows currently to John = 115 miles.

We need to find the distance between town and John's current location.

For the problem, we can clearly see that Town is at 160 miles away but when John passes the marker shows 115 miles.

So, it's just the difference between 160 miles and 115 miles.

In order to find that difference, we need to subtract those two numbers.

160miles - 115miles = 45 miles.

So, we could say the distance between town and John's current location is 45 miles.

4 0
3 years ago
An object is thrown upward from the top of a 160 foot building with an initial velocity of 48 feet per second. The height h of t
inn [45]

Answer:

t=5s

Explanation:

From free falling objects we know that height is equal to:

h=h_{o}+v_{oy}t+\frac{1}{2}gt^{2}

From the exercise we know that

h_{o}=160ft\\v_{oy}=48ft/s\\g=-32 ft/s^{2}

Being said that, we can calculate how long would it take to the object to hit the ground knowing that the height at that point is 0

0=160ft+(48ft/s)t-\frac{1}{2}(32ft/s^2)t^2

Solving the quadratic formula we got that

t=\frac{-b±\sqrt{b^{2}-4ac}}{2a}

a=-16\\b=48\\c=160

t=-2s or t=5s

Since time can not be negative the logical answer is <u><em>t=5s</em></u>

So, the object hit the ground at 5s

6 0
3 years ago
Read 2 more answers
Please help! 34 points!
solmaris [256]

I believe the answer is Compression C

8 0
3 years ago
Read 2 more answers
A ball is thrown horizontally from the top of a building 100m high. The ball strikes the ground at a point 120 m horizontally aw
astraxan [27]

26.54 m/s  is the magnitude of its velocity just before it strikes the ground

h=100m,v=20m/s,g=9.8m/s

time it takes to reach the ground,

[t=\sqrt2h/g],[=\sqrt2*100/9.8=4.51s]

x= 120m

t= 4.52

v= x/t

v= 120/4.52

v= 26.54 m/s

The "speed at which an object changes its location" can be expressed using a vector number called velocity. Consider a person who moves swiftly while taking two steps forward and two steps back while remaining in one location. Velocity is a vector quantity. Therefore, velocity is cognizant of direction. The direction must be taken into account when determining an object's velocity. A speed of 55 mph is not enough information. The direction must be used to appropriately depict the item's velocity. Simply said, the direction of the velocity vector indicates the direction of motion of an object.

To know more about  velocity visit : brainly.com/question/16379705

#SPJ9

5 0
1 year ago
A bicycle is moving from rest with a constant acceleration of 3 m/s^2 calculate the final velocity of the car if the distance mo
iragen [17]

Answer:

6m/s

Explanation:

  • Acclⁿ = 3m/s²
  • Displacement = 6m .
  • Initial velocity = 0m/s .
  • Final velocity = ?

We know that ,

\longrightarrow 2as = v² - u²

\longrightarrow 2 * 3m/s² * 6m = v² - (0)²

\longrightarrow v² = 36m²/s²

\longrightarrow v = √36 m²/s²

\longrightarrow v = 6m/s

8 0
3 years ago
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