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Harlamova29_29 [7]
2 years ago
12

"it was so cold yesterday that the temperature only reached 275." which temperature scale is being used? what would be the corre

sponding temperature on the other two scales?
Physics
2 answers:
kow [346]2 years ago
7 0
Remembering back to science I believe that temperature is on the Kelvin scale. The corresponding temperature on the Celsius scale would be very close to zero degrees which is the freezing point. The corresponding temperature on the Fahrenheit scale would be 32 degree which again is the freezing point.
Luba_88 [7]2 years ago
7 0
Answer is: Kelvin.
1) <span>The temperature </span>in degrees Celsius (°C) is equal to the temperature<span> in Kelvin (K) minus 273,15.
</span>T(°C)<span> = </span>T(K) - 273.15 = 275 - 273,15 = 1,85°C.
2) The temperature in degrees Fahrenheit (°F) is equal to the temperature in Kelvin (K) times 9/5, minus 459.67:
T(°F) = T(K) · 9/5 - 459,67 = 275 · 1,8 - 459,67 = 35,33°F.

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What is the angular displacement of the wheel between t = 5 s and t = 15 s?
Mkey [24]

The question seems incomplete. The complete text is:

a)What is the angular displacement of the wheel between t = 5 s and t = 15 s

b)What is the angular velocity of the wheel at 15 s

And it refers to the attached figure.

a) 25 rad

The graph shown represent the angular position of the wheel at different times.

Therefore, we can simply calculate the  angular displacement between two times by calculating the difference between the angular position at t2 and the angular position at t1.

At t_1 = 5 s, the angular position from the graph is \theta_1 = 100 rad

At t_2 = 15 s, the angular position from the graph is \theta_2 = 125 rad

Therefore, the angular displacement is

\Delta \theta= \theta_2 - \theta_1 = 125-100 = 25 rad

2) -5.0 rad/s

For a angular displacement vs time graph, the angular velocity at any time is simply equal to the slope of the curve at that time.

Here  we want to calculate the angular velocity at t = 15 s, so we have to calculate the slope at that time.

By noting that the slope is constant in the last part of the motion, we find that the slope between 10 s and 20 s is:

\frac{\Delta \theta}{\Delta t}=\frac{100 rad - 150 rad}{20 s - 10 s}=-5.0 rad/s

This slope is constant between 10 s and 20 s, so the angular velocity of the wheel at t = 15 s

\omega = -5.0 rad/s

5 0
2 years ago
What is the symbol name?
murzikaleks [220]

Answer:

cell

Explanation:

here are all the symbols-

hope this helps, take care and stay safe

7 0
2 years ago
A truck is moving north word at a constant speed the momentum of the car is
nataly862011 [7]

Answer:

its constant i think

Explanation:

or its stable dunno which term will they be using

6 0
2 years ago
How much heat is required to convert 5.53 g of ice at -12.0 ∘C to water at 24.0 ∘C? (The heat capacity of ice is 2.09 J/(g⋅∘C),
fredd [130]

Answer:

2.55 × 10³ J =2.55 kJ

Explanation:

Specific heat capacity of ice =  37.8 J / mol °C

Specific heat capacity of water = 76.0 J/ mol °C

Ice at -12 °C is converted to ice at 0 °C by absorbing heat Q₁

Ice at 0°C melts to water at 0 °C. Let Heat  absorbed during this phase change be Q₂ .

Let heat  absorbed to raise the temperature of water from 0 C to 24°C be Q₃ .

Total heat = Q = Q₁ + Q₂ + Q₃

Q₁ = (37.8 j/mol C )(5.53 g /18.01532 g/ mol )( 0-(-12)) = 139.23749 j

Q₂ =(5.53 g/18.01532 g H₂O / mol ) (6.02 x10³ j) = 1847.905 j

Q₃ = (76 j/mol C) ( (5.53 g/18.01532 g H₂O / mol )(24-0) = 559.8968 j

Total Heat required = Q = 139.23749 j + 1847.905 j + 559.8968 j

= 2547.039 j = 2.55 × 10³ J =2.55 kJ

5 0
3 years ago
What is the difference between convex and concave mirrors and lens?
Sidana [21]
Concave makes things smaller and convex makes things bigger
5 0
2 years ago
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