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aleksklad [387]
3 years ago
12

Write the equation of the line that is perpendicular to y = - 1/2x + 5 and passes through the point (6, -8)

Mathematics
1 answer:
Tom [10]3 years ago
6 0

Answer:

Hmmm... I'm not sure :( sorry :(

Step-by-step explanation:

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Use the diagram to determine which statement is true
Dahasolnce [82]

The answer is d.

Finding area of ABCD :

  1. Find side length
  • side = √3² + 4²
  • side = 5

    2. Apply formula to find area

  • area = 5²
  • area = 25

Finding area of GHIA :

  • area = 4²
  • area - 16

Finding area of DEFG :

  • area = 3²
  • area = 9

Now, let's see whether is true.

  • Area (ABCD) - Area (GHIA) = Area (DEFG)
  • 25 - 16 = 9
  • 9 = 9

∴ Hence, it is proved √

7 0
1 year ago
A sphere and cylinder have the same radius and height. The volume of the cylinder is 30m^3. What is the volume of the sphere?
Aleonysh [2.5K]

Answer:

15 is the volume I hope I helped

5 0
3 years ago
Maura runs 5 miles in 1.25 hours. Ava runs 3 miles in 50 minutes or 0.83¯ hour.<br> Who runs faster?
kenny6666 [7]

Answer:

║⊕║∵°·∵∴Hello :)∴∵·°∵∴║⊕║

Your answer should be:

Maura runs faster.

Step-by-step explanation:

I hope this helped!

<em>Brainliest appreciated</em>

<h2><em>Have a good day!</em></h2>
8 0
3 years ago
What can you say about the sum of consecutive odd numbers starting with 1? that is, evaluate 1, 1c3, 1c3c5, 1c3c5c7, and so on,
Mice21 [21]

Let us add consecutive odd numbers and try to find any relationship.

1. 1

2. 1+3 = 4 ( square of 2 i.e 2^{2} )

3. 1+3+5 = 9 ( 3^{2} )

4.  1+3+5+7 =  16 (4^{2} )

5. 1+3+5+7+9 = 25 (5^{2} )

6. 1+3+5+7+9+11 = 36 ( 6^{2} )

7. 1+3+5+7+9+11+13 = 49 (7^{2} )

If we notice, the sum of the consecutive odd integers in each case is equal to the square of the place where it lies. For example, the sum of numbers in seventh place is equal to 7^{2}. The sum of the numbers in the fifth line is equal to 5^{2}.

4 0
3 years ago
Assuming that the sample mean carapace length is greater than 3.39 inches, what is the probability that the sample mean carapace
joja [24]

Answer:

The answer is "".

Step-by-step explanation:

Please find the complete question in the attached file.

We select a sample size n from the confidence interval with the mean \muand default \sigma, then the mean take seriously given as the straight line with a z score given by the confidence interval

\mu=3.87\\\\\sigma=2.01\\\\n=110\\\\

Using formula:

z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}  

The probability that perhaps the mean shells length of the sample is over 4.03 pounds is

P(X>4.03)=P(z>\frac{4.03-3.87}{\frac{2.01}{\sqrt{110}}})=P(z>0.8349)

Now, we utilize z to get the likelihood, and we use the Excel function for a more exact distribution

=\textup{NORM.S.DIST(0.8349,TRUE)}\\\\P(z

the required probability: P(z>0.8349)=1-P(z

4 0
2 years ago
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