3 years ago

If heat is added to a boiling liquid, what happens to the temperature of the liquid?

Chemistry

1 answer:

stealth61 [152]3 years ago

4 0

Answer: C

Explanation:

Answer is "It does not change"

Hope this helps!

You might be interested in

Which of the following metals will react with water to produce a metal hydroxide and hydrogen gas?

Pachacha [2.7K]

Na is the answer hope it help

7 0

3 years ago

HURRY !!!!!! How did kelper describe the planets Orbits ?

Andrei [34K]

Kepler's Laws of Planetary Motion. While Copernicus rightly observed that the planets revolve around the Sun, it was Kepler who correctly defined their orbits.

Sorry about the holds, copied it from google...

8 0

3 years ago

A mixture of iron and sulfur can be separated by A.magnetic attraction

Elenna [48]

A. Magnetic attraction

6 0

3 years ago

What evidence would support Maria's claim that the fossilized remains are that of a bird, class Aves, instead of a turtle, class

lora16 [44]

Your answer would be C.

6 0

3 years ago

Read 2 more answers

A sample of He gas (3.0 L) at 5.6 atm and 25°C was combined with 4.5 L of Ne gas at 3.6 atm and 25°C at constant temperature in

In-s [12.5K]

Answer:

3.6667

Explanation:

For helium gas:

Using Boyle's law

${P_1}\times {V_1}={P_2}\times {V_2}$

Given ,

V₁ = 3.0 L

V₂ = 9.0 L

P₁ = 5.6 atm

P₂ = ?

Using above equation as:

${P_1}\times {V_1}={P_2}\times {V_2}$

${5.6}\times {3.0}={P_2}\times {9.0} atm$

${P_2}=\frac {{5.6}\times {3.0}}{9.0} atm$

${P_1}=1.8667\ atm$

The pressure exerted by the helium gas in 9.0 L flask is 1.8667 atm

For Neon gas:

Using Boyle's law

${P_1}\times {V_1}={P_2}\times {V_2}$

Given ,

V₁ = 4.5 L

V₂ = 9.0 L

P₁ = 3.6 atm

P₂ = ?

Using above equation as:

${P_1}\times {V_1}={P_2}\times {V_2}$

${3.6}\times {4.5}={P_2}\times {9.0} atm$

${P_2}=\frac {{3.6}\times {4.5}}{9.0} atm$

${P_1}=1.8\ atm$

The pressure exerted by the neon gas in 9.0 L flask is 1.8 atm

Thus total pressure = 1.8667 + 1.8 atm = 3.6667 atm.

6 0

3 years ago