The early precambrian atmosphere consisted primarily of nitrogen and carbon dioxide with almost no oxygen.
<span>Today, the atmosphere contains about 20% oxygen, less carbon dioxide and similar amounts of nitrogen. </span>
<span>Photosynthetic green-leaf plants and trees are largely responsible for the change, converting carbon dioxide to oxygen.</span>
Answer:
= 9.28 g CO₂
Explanation:
First write a balanced equation:
CH₄ + 2O₂ -> 2H₂O + CO₂
Convert the information to moles
7.50g CH₄ = 0.46875 mol CH₄
13.5g O₂ = 0.421875 mol O₂
Theoretical molar ratio CH₄:O₂ -> 1:2
Actual ratio is 0.46875 : 0.421875 ≈ 1:1
If all CH₄ is used up, there would need to be more O₂
So O₂ is the limiting reactant and we use this in our equation
Use molar ratio to find moles of CO₂
0.421875 mol O₂ * 1 mol CO₂/2 mol O₂=0.2109375 mol CO₂
Then convert to grams
0.2109375 mol CO₂ = 9.28114 g CO₂
round to 3 sig figs
= 9.28 g CO₂
Question:
How many neutrons are there in 186W
Answer:
112
hope it helps (^^)
# Cary on learning
Answer:
0.13 M
Explanation:
The reaction equation is;
NaOH(aq) + KHC8H4O4(aq) ------> KNaC8H4O4(aq) + H2O(l)
Molar mass of KHP = 204.22 g/mol
Amount of KHP= mass/ molar mass = 0.3365 g/204.22 g/mol = 1.65 × 10^-3 moles
n= CV
Where;
C= concentration
V= volume in dm^3
n= number of moles
C= n/V = 1.65 × 10^-3 moles × 1000/250 = 6.6 × 10^-3 M
If 1 mole of KHP reacts with 1 mole of NaOH
1.65 × 10^-3 moles of KHP will react with 1.65 × 10^-3 moles of NaOH
From
n= CV
We have that only 12.44 ml of NaOH reacted
C= n/V = 1.65 × 10^-3 moles × 1000/12.44
C= 0.13 M
At the equivalence point, the KHP solution turned light pink.
Answer:
C: liquid
Explanation:
Liquid has the set volume as it cannot be compressed or 'expanded' like a gas. However, liquids will take the shape of the container you put them in so their shape can change.
