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Luda [366]
3 years ago
13

1. The fourth principle electronic level has:

Chemistry
1 answer:
attashe74 [19]3 years ago
5 0

Answer:

the fourth level can hold up to 32 electrons: 2 in the s orbital, 6 in the three p orbitals, 10 in the five d orbitals, and 14 in the seven f orbitals.

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borishaifa [10]
Magnesium and silver
4 0
3 years ago
How many pi bonds are in the oxalate ion (C2O42-)?
suter [353]

Answer:there are 13

Explanation:

4 0
3 years ago
PLSSSSS HELP I DONT GET THIS PROBLEMMMM
Aleks [24]

Answer:

C. 7370 joules.

Explanation:

There is a mistake in the statement. Correct form is described below:

<em>Using the above data table and graph, calculate the total energy in Joules required to raise the temperature of 15 grams of ice at -5.00 °C to water at 35 °C. </em>

The total energy needed to raise the temperature is the combination of latent and sensible heats, all measured in joules, and represented by the following model:

Q = m\cdot [c_{i} \cdot (T_{2}-T_{1})+L_{f} + c_{w}\cdot (T_{3}-T_{2})] (1)

Where:

m - Mass of the sample, in grams.

c_{i} - Specific heat of ice, in joules per gram-degree Celsius.

c_{w} - Specific heat of water, in joules per gram-degree Celsius.

L_{f} - Latent heat of fusion, in joules per gram.

T_{1} - Initial temperature of the sample, in degrees Celsius.

T_{2} - Melting point of water, in degrees Celsius.

T_{3} - Final temperature of water, in degrees Celsius.

Q - Total energy, in joules.

If we know that m = 15\,g, c_{i} = 2.06\,\frac{J}{g\cdot ^{\circ}C}, c_{w} = 4.184\,\frac{J}{g\cdot ^{\circ}C}, L_{f} = 334.72\,\frac{J}{g}, T_{1} = -5\,^{\circ}C, T_{2} = 0\,^{\circ}C and T_{3} = 35\,^{\circ}C, then the final energy to raise the temperature of the sample is:

Q = (15\,g)\cdot \left[\left(2.06\,\frac{J}{g\cdot ^{\circ}C} \right)\cdot (5\,^{\circ}C)+ 334.72\,\frac{J}{g} + \left(4.184\,\frac{J}{g\cdot ^{\circ}C}\right)\cdot (35\,^{\circ}C) \right]

Q = 7371.9\,J

Hence, the correct answer is C.

8 0
2 years ago
Convert 75g of NaOH to moles
ANTONII [103]

Answer:

75g and I no inglish I my espanish perfec

Explanation:

3 0
2 years ago
Sulfur dioxide gas reacts with oxygen gas for form sulfur trioxide gas. the equilibrium constant for the reaction at 6000c is 4.
Art [367]
When the balanced equation for this reaction is:

            2SO3 → 2SO2 + O2 so, by using ICE table:

initial    0.391              0          0.125m

change  -X               +2X           +X

Equ     (0.391-X)         2X           0.125+X

when Keq = concentration of products / concentration of reactants

so, by substitution

    4.34  = [2X]^2 * [0.125+X] / [0.391-X]^2  by solving for X

∴ X = 0.357 m 

∴ the concentration of SO2 = 2x = 2 * 0.357 

                                               = 0.714 m 
3 0
3 years ago
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