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Norma-Jean [14]
2 years ago
11

If you double the volume of a sample of gas and then doubled the volume again without changing its pressure, how would this abso

lute temperature of the gas be affected
Chemistry
2 answers:
IRINA_888 [86]2 years ago
7 0

Answer:

Explanation:

Increasing Volume while maintaining constant pressure requires a proportional increase in Temperature so the gas pressure will be maintained as constant.

Consider...

V₁ = V₁     V₂ = 4V₁

T₁ = T₁      T₂ = ?

Charles Law => T ∝ V at constant P ... that is, increasing temperature generates a proportional increase in volume to maintain constant pressure.

Empirical Charles Law Relation is ...

V₁/T₁ = V₂/T₂ => T₂ = T₁(V₂/V₁) = T₁(4V₁/V₁) = 4T₁

Increasing Volume of a gas by 4 times requires a 4 times increase in absolute temperature in order to maintain constant pressure.

aliya0001 [1]2 years ago
7 0

absolute temperature will increase fourfold

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Match the prefixes. 1. 1 hex- 2. 2 eth- 3. 3 prop- 4. 4 hept- 5. 5 non- 6. 6 dec- 7. 7 pent- 8. 8 but- 9. 9 meth- 10. 10 oct-
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All these prefixes are commonly employed in the nomenclature in organic chemistry. These are associated with organic compounds, such as alkanes, alkenes, alcohols and carboxylic acids -and these prefixes are known as word root.

<h3>The answers would be:</h3><h3>a) 1 - meth</h3>

Meth is associated with the number one, in that it signifies the presence of one carbon in the compound in concern. For instance, a one carbon alkane would be known as methane -with <em>ane </em>being indicative of the compound being an alkane, and meth denoting the presence of one carbon

<h3>b) 2 - eth</h3>

Eth is the associated prefix with the number 2 as it denotes the presence of 2 carbon atoms in the compound. For instance, the compound ethene gets it name for having 2 carbon atoms (denoted by eth). The eth acts as a prefix to the characteristic <em>ene</em> of alkenes.

<h3>c) 3 - prop</h3>

Prop is the prefix that signifies the presence of 3 carbons in the compound in concern. For instance, propanol is a three carbon alcohol, which we can tell by the name. Prop indicating three carbons in the compound, and <em>anol</em> being indicative of the compound being an alcohol.

<h3>d) 4 - but</h3>

But is associated with the number one, in that it denotes the presence of 4 carbons in the compound. For instance, a 4 carbon carboxylic acid would be known as butanoic acid -with anoic<em> </em>being indicative of the compound being a carboxylic acid, and but signifying the presence of four carbons.

<h3>e) 5 - pent</h3>

Pent is the associated prefix with the number five as it denotes the presence of five carbon atoms in the compound. For instance, the compound pentene gets it name for having five carbon atoms (denoted by pent). The pent acts as a prefix to the characteristic <em>ene</em> of alkenes.

<h3>f) 6 - hex</h3>

Hex is the prefix that signifies the presence of six carbons in the compound in question. For instance, a six carbon alkane would be known as hexane -with <em>ane </em>being indicative of the compound being an alkane, and hex denoting the presence of one carbon

<h3>g) 7 - hept</h3>

Hept is the associated prefix with the number seven as it denotes the presence of seven carbon atoms in the compound. For instance, the compound heptene gets it name for having seven carbon atoms (denoted by hept). The hept acts as a prefix to the characteristic <em>ene</em> of alkenes.

<h3>h) 8 - oct</h3>

Oct is the prefix that is associated with the number 8. This is because it denotes the presence of eight carbon atoms in the compound. For instance, the compound octane gets it name for having eight carbon atoms (denoted by oct). The oct acts as a prefix to the characteristic <em>ane</em> of alkanes.

<h3>i) 9 - non</h3>

Non is the prefix that is associated with the number nine, and thus denotes the presence of nine carbon atoms in the compound. For instance, for alkanes, a nonane would be a nine carbon atom alkane, with non denoting the presence of nine carbon atoms, and <em>ane</em> being indicative that the compound it an alkane.

<h3>j) 10- dec</h3>

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<h3>Hope this helps!</h3>
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