If you double the volume of a sample of gas and then doubled the volume again without changing its pressure, how would this abso
2 answers:
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Answer:
Heating this gas to 55 °C will raise its volume to 6.87 liters.
Assumption: this gas is ideal.
Explanation:
By Charles's Law, under constant pressure the volume of an ideal gas is proportional to its absolute temperature
(the one in degrees Kelvins.)
Alternatively, consider the ideal gas law:
.
is the number of moles of particles in this gas.
is the ideal gas constant.
is the pressure on the gas. The question states that the pressure on this gas is constant.
Therefore the volume of the gas is proportional to its absolute temperature.
Either way,
.
.
For the gas in this question:
- Initial volume:
.
Convert the two temperatures to degrees Kelvins:
- Initial temperature:
.
- Final temperature:
.
Apply Charles's Law:
.
Answer:
H2S has a bent geometry, while BeH2 has a linear geometry because: presence of lone pair in H2S
Absence of Lone pair in BeH2
Explanation:
<u>Structure of H2S :</u>
Atomic number of S = 16 = 1s(2 )2s(2) 2p(6) <u>3s(2 )3p(4)</u>
Outer most shell has 6 electron
Valence electron (Involved in bonding) = 6
Out of these 6 electrons ,
2 electrons are formed in bonding with Hydrogen
Rest 4 are non- bonding and present as lone - pair
H2S exist - sp3 hybridisation
There are 2-Lone pair on S in H2S (look at the image attached)
<u>Structure of H2S :</u>
Atomic number of Be = 4 = 1s(2 ) 2s(2)
Valence electron (Involved in bonding) = 2
These 2- electron are involved in bonding with two Hydrogen and form liner shape.*Form sp - hybridized
Hence shape is linear because it has non - lone pair.
VSEPR : <u><em>According to this theory lone pair causes repulsion to the bond and cause unstability in the molecule.</em></u>
<u><em>Hence the bonds shifts away from lone pairs . This is why H-S bonds in H2S shifts way from lone pair</em></u>
Answer:
Average atomic mass = 79.9034 amu
Explanation:
The formula for the calculation of the average atomic mass is:
Given that:
<u>For first isotope: </u>
% = 50.69 %
Mass = 78.9183 amu
<u>For second isotope: </u>
% = 49.31 %
Mass = 80.9163 amu
Thus,
<u>Average atomic mass = 79.9034 amu</u>