1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
borishaifa [10]
2 years ago
8

Describe the differences between polyp and medusa

Chemistry
1 answer:
stealth61 [152]2 years ago
5 0
One difference is that some animals are polyp and some are medusa.


The other difference is that some animals have medusa in their life or polp in their life cycle.


Hope these two differences helps :D
You might be interested in
If 25.8 grams of BaO dissolve in enough water to make a 212 gram solution, what is the percent by mass of the solution?
Scorpion4ik [409]
Mass of solute = 25.8 g

mass solution = 212 g

% =(  mass of solute / mass solution ) x 100

% = ( 25.8 / 212 ) x 100

% = 0.122 x 100

= 12.2 %



6 0
3 years ago
Read 2 more answers
What volume of a 2.10 M NaCl solution is
cluponka [151]

Answer:

146.3g NaCl (mol NaCl/58.44g NaCl) = 2.50 mol NaCl

1.5M NaCl = 1.5 mol NaCl / 1 L = 2.5 mol NaCl / x L, solve for x

x L = 2.5 mol NaCl / 1.5 mol NaCl = 1.66 L

It gives the answer and all the working.

To put it another way:

Dividing the amount required by the molar mass

we quickly see that 2.5 moles are required.

One litre of 1.5 molar solution gives 1.5 moles

we need a further mole, which is 2/3 of 1.5 so 2/3 of a litre.

3 0
2 years ago
How much heat in j is giving out when 85.0g of lead cools from 200.0 c to 10.0c
photoshop1234 [79]

Answer:

q = - 2067.2 J of Heat is giving out when 85.0g of lead cools from 200.0 c to 10.0 c.

Explanation:

The Specific Heat capacity of Lead is 0.128 \frac{J}{g\ ^{0}C}

This means, increase in temperature of 1 gm of lead by 1 ^{0}\ C will require 0.128 J of heat.

Formula Used :

q = m.c.\Delta T

q = amount of heat added / removed

m = mass of substance in grams = 85.0 g

c = specific heat of the substance = 0.128

q = m.c.\Delta T = Change in temperature

                                          = final temperature - Initial temperature

                                          = 10 - 200

                                          = -190 ^{0}\ C

put value in formula

q = -  85\times 0.128\times 190

On calculation,

q = - 2067.2 J

- sign indicates that the heat is released in the process

5 0
3 years ago
Symptoms of a mental disorder are ways of
kkurt [141]

Answer: thinking

Explanation:

6 0
2 years ago
Where is the carbon in a temperate
tangare [24]

In the high temperate

8 0
3 years ago
Other questions:
  • 36.665m=____________cm
    11·1 answer
  • Sam wished to investigate how fertilizer run-off affects the growth of algae in freshwater lakes and streams. He set his experim
    6·1 answer
  • A gas mixture consists of 4 kg of O2, 5 kg of N2, and 7 kg of CO2. Determine (a) the mass fraction of each component, (b) the mo
    10·1 answer
  • Calculate the number of grams of C2H6 in 4.6 miles of C2H6
    10·1 answer
  • What element is used as a shield to protect from radioactive substances?
    13·1 answer
  • Element X is a solid that is brittle, lacks luster,and has six valence electrons. In which group on the Periodic Table would ele
    9·1 answer
  • Calculate the number of moles of NaOH that are needed to react with 500.0 g of
    7·1 answer
  • What would happen if a TLC plate was placed in a jar where the solvent level was above the level of the origin (sample spot)? Wh
    9·2 answers
  • HELP ME ASAP PLEASE<br><br> I need the answers I’m in a hurry
    8·1 answer
  • What information about a molecule can you determine from its<br> chemical formula?
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!