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Amanda [17]
3 years ago
13

Nitroglycerin (C3H5N3O9) is a powerful explosive. Its decomposition may be represented by 4C3H5N3O9 → 6N2 + 12CO2 + 10H2O + O2

Chemistry
1 answer:
almond37 [142]3 years ago
8 0

Answer:

the guy infront of me

Explanation:

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A student needs to prepare a stock solution for the lab - 500.0 ml of 0.750 m nitric acid. The student is provided with concentr
dlinn [17]

Molarity of concentrated nitric acid = 15.9 M

Volume of the stock solution to be prepared = 500.0 mL

Concentration of the stock that is to be prepared = 0.750 M

Calculating moles from molarity and volume of stock:

500.0mL*\frac{1L}{1000mL}*0.750\frac{mol}{L}  =0.375 mol HNO_{3}

Calculating volume of concentrated nitric acid to be taken for the preparation of stock solution:

0.375mol*\frac{1L}{15.9mol} =0.0236 L

Converting L to mL:

0.0236L*\frac{1000mL}{1L} = 23.6 mL

Volume of distilled water to be added to 23.6 mL of 15.9 M nitric acid to get the given concentration = 5000.0mL-23.6mL=976.4 mL

Therefore, 976.4 mL distilled water is to be added to 23.6 mL of 15.9 M nitric acid solution to prepare 500.0 mL of 0.750M nitric acid.

6 0
4 years ago
2. Which of the following solution contains more salt?<br> A. 3M<br> B. 1M<br> C. 0.5M<br> D. 0.25M
Tanya [424]

Answer: 0.25M

Explanation: Because of the highest concentration of water and, if they are all the same volume, the greatest amount of water assuming it is a solid solute in a water solution.

5 0
3 years ago
When rubidium ions are heated to a high temperature, two lines are observed in its line spectrum at wavelengths (a) 7.9 × 10−7 m
svetlana [45]

Answer:

The frequencies of the two lines are:

a) 3.79\times 10^{14} s^{-1}

b)7.14\times 10^{14} s^{-1}

When we heat rubidium compound we will see red color.

Explanation:

\nu=\frac{c}{\lambda }

c = speed of light

\lambda = wavelength of light

a) Frequency of the light when wavelength is equal to 7.9\times 10^{-7} m

\nu=\frac{c}{\lambda }

\nu=\frac{3\times 10^8m/s)}{7.9\times 10^{-7}}

\nu=3.79\times 10^{14} s^{-1}

This frequency corresponds to red light

b) Frequency of the light when wavelength is equal to 4.2\times 10^{-7} m

\nu=\frac{c}{\lambda }

\nu=\frac{3\times 10^8m/s)}{4.2\times 10^{-7}}

\nu=7.14\times 10^{14} s^{-1}

This frequency corresponds to violet light

When we heat rubidium compound we will see red color.

4 0
3 years ago
What is the 10th element of the periodic table?
fredd [130]

Answer:

Neon

Explanation:

6 0
4 years ago
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Consider the reaction below. mc009-1.jpg If the reaction is at dynamic equilibrium at 500 K, which statement applies to the give
Bas_tet [7]
The answer is ( The concentrations of the products and reactants do not change.)
6 0
4 years ago
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