Nce?

Answer:

Revisar las respuestas a cada problema, como se muestra mas adelante.

Explanation:

Para poder solucionar esta serie de problemas debemos de utilizar la segunda ley de Newton, la cual nos dice que la sumatoria de fuerzas sobre un cuerpo debe de ser igual producto de la masa por la aceleracion.

De esta manera tenemos:

ΣF = m*a

donde:

F = fuerza [N]

m = masa [kg]

a = aceleracion [m/s^2]

1 )

F = m*a

60 = m*4

m = 15[kg]

2)

F = m*a

a = 250/50

a = 5 [m/s^2]

3)

F = m*a

F = 80*2.5

F = 200 [N]

4)

F = m*a

800 = 1500*a

a = 0.533[m/s^2]

5)

F = m*a

100 = 500*a

a = 100/500

a = 0.2 [m/s^2]

7 0

4 years ago

A man tries to push a 200 kg Car that moves at a acceleration 0.50 m/s2. The man is able to displace the car 10 m. How much work

yawa3891 [41]

The work done by the man pushing the car over the given distance is 1000J.

Given the data in the question;

Mass of car; $m = 200kg$

Acceleration of the car; $a = 0.5m/s^2$

Distance covered by the car; $d = 10m$

Work done; $W = \ ?$

Work done is simply defined as the energy transfer that takes place when an object is either pushed or pulled over a certain distance by an external force. It is expressed as;

$Work\ done = f * d$

Where f is force applied and d is distance travelled.

To determine the work done by the man, we first solve for the force applied F.

From Newton's Second Law; $Force \ F = m * a$

We substitute our given values into the expression

$F = m * a \\\\F = 200kg * 0.5m/s^2\\\\F = 100kg.m/s^2$

Next we substitute our values into the expression of work done above.

$Work \ done = f * d\\\\Work \ done = 100kg.m/s^2 * 10m\\\\Work \ done = 1000kgm^2/s^2\\\\Work \ done = 1000J$

Therefore, the work done by the man pushing the car over the given distance is 1000J.

Learn more about work done: brainly.com/question/26115962

7 0

2 years ago

a satellite maintains an orbit equidistant from the earth at all points along its orbital path hiw is the satellite affected by

Paraphin [41]

ANY closed orbit exists because of the centripetal force of gravity.
Without the force of gravity, the satellite would simply sail away
in a straight line.

The orbit you're describing happens to be a circular orbit, but it
doesn't have to be circular.

5 0

4 years ago

A 2.4 kg box has an initial velocity of 3.6 m/s upward along a plane inclined at 27◦ to the horizontal. The coefficient of kinet

Vika [28.1K]

Answer:

d= 1.18 m

Explanation:

In abscense of friction, total mechanical energy must be constant, i.e.,

ΔK + ΔU = 0

As we are told that there exists a kinetic friction between the box and the plane, we need to take into account the work done by the friction force in the equation, as follows:

ΔK + ΔU = Wnc (1)

If we take as our zero gravitational potential energy reference, the height at which the box is sent upward, we can write the following equations for the different terms in (1):

ΔK = Kf- K₀ = 0 - 1/2*m*v₀² = -1/2*2.4kg* (3.6)²(m/s)² = -15.6 J

ΔU = Uf - U₀ = m*g*h = *m*g*d*sin θ = 2.4 kg*9.81 m/s²*d*0.454 = 10.7*d J

Wnc = Ff. d* cos (180º) = μk*N*d*cos(180º) (2)

The friction force always opposes to the displacement, so the angle between force and displacement is 180º.

The normal force, as is always perpendicular to the surface, takes the value needed to equilibrate the component of the weight perpendicular to the incline, as follows:

N = m*g*cosθ = 2.4 kg*9.81 m/s²*cos 27º = 21 N

Replacing in (2):

Wnc = 0.12*21*cos (180º) = -2.52*d J

Replacing in (1):

-15.6 J + 10.7*d J = -2.52*d J

Solving for d:

d = 1.18 m

7 0

4 years ago

Liam is two-years old. His mother is concerned about his behavior. Liam is very different from how his sister Briana was when sh

slavikrds [6]

Answer:

Autism

Explanation:

Those are some symptoms of autism that you described

5 0

3 years ago