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AnnyKZ [126]
3 years ago
14

Fatigue strength is generally significantly improved by using high steel a. alloy b. yield c. hardened d. ultimate strength e. a

ll of these
Physics
1 answer:
Gala2k [10]3 years ago
7 0

Answer:

e. all of these

Explanation:

The fatigue strength is improved by then high alloy steels , high yield steels , high hardened steel , high ultimate steel .

Due to the formation of the improved materials in alloy steels will increase the fatigue strength . Similarly for a high yield steels and hardened steels these cycles to failure will improve .

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A Chef is looking for a new frying pan that will allow her to cook food quickly at temperatures above 500°C. Use the data provid
makvit [3.9K]

Answer:

Explanation:

1st one

What is your evidence?

Very heavy professional or restaurant pans will have iron handles, while those for home use will be made of brass or stainless steel. All are perfectly safe for oven use.

6 0
2 years ago
On sunday a strong gale blows near beth’s house. the best estimate for the wind speed is ____ miles/hour.
Rufina [12.5K]

Answer:

B. 47-54 miles/hour

Explanation:

Gale is a strong wind which is depicted by red warning flag. According to U.S. National Weather Service gale is a sustained surface wind. It is also used to refer winds from tropical coastal areas.

On the basis of force of wind gale is divided in four groups:

  1. Near gale   - 32-38 mph
  2. Gale            - 39-46 mph
  3. Strong gale - 47-54 mph
  4. Storm           - 55-63 mph
8 0
3 years ago
In a simplified model of a hydrogen atom, the electron moves around the proton nucleus in a circular orbit of radius 0.53×10−10m
Ksenya-84 [330]

Answer

given,

radius of the circular orbit, r = 0.53 x 10⁻¹⁰ m

mass of electron, M = 9.11 x 10⁻³¹ Kg

charge of electron, q₁ = 1.6 x 10⁻¹⁹ C

                                q₂ = 1.6 x 10⁻¹⁹ C

we know, force between two charges

F = \dfrac{kq_1q_2}{r^2}

F = \dfrac{9\times 10^9\times (1.6\times 10^{-19})^2}{(0.53\times 10^{-10})^2}

  F = 8.20 x 10⁻⁸ N

b) using newton's second law

F = m a

m a =  8.20 x 10⁻⁸

a =\dfrac{8.20\times 10^{-8}}{9.11\times 10^{-31}}

    a = 9 x 10²² m/s²

c) speed of the electron

 a =\dfrac{v^2}{r}

 9\times 10^{22} =\dfrac{v^2}{0.53\times 10^{-10}}

   v² = 4.77 x 10¹²

  v = 2.18 x 10⁶ m/s

d) the period of the circular motion.

    T=\dfrac{2\pi}{\omega}

    T=\dfrac{2\pi r}{v}

    T=\dfrac{2\pi\times 0.53\times 10^{-10}}{2.18\times 10^6}

          T = 1.53 x 10⁻¹⁶ s

8 0
3 years ago
Read 2 more answers
In an electrical circuit 200mC of charge flows through a 50kohm resistor in 90 seconds. What is the power
ss7ja [257]

Answer: 0.2464\ W

Explanation:

Given

Charge Q=200\ mC

Resistance R=50\ k\Omega

Time t=90\ s

Charge is the amount of current flown in a particular time

Q=It\\\Rightarrow 200\times 10^{-3}=I\times 90\\\\\Rightarrow I=\dfrac{200\times 10^{-3}}{90}\\\\\Rightarrow I=2.22\times 10^{-3}\ A

Power is the given by P=I^2R

Insert values

\Rightarrow P=\left(2.22\times 10^{-3}\right)^2\times 50\times 10^3\\\\\Rightarrow P=246.42\times 10^{-3}\ W\\\\\Rightarrow P=0.2464\ W

The power is in the circuit is 0.2464\ W.

8 0
2 years ago
C) m1:<br><br> D) m2: <br><br> E) r. <br><br> Please help me I need help now
Nesterboy [21]
A) F  = gravitational force

b) G = universal gravitational constant (6.67 × 10-11 N-m2/kg2)

c) m1 = mass of the body 1

d) m2 = mass of body 2

e) r = radius or distance between the two bodies.

Hope this helps!
6 0
3 years ago
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