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True [87]
3 years ago
12

3- A car was traveled 110 meters in 5.5 seconds. What was the car's velocity?*

Physics
2 answers:
Tatiana [17]3 years ago
7 0

<u>Answer</u>:

20 m/s

<u>Explanation</u>:

* velocity = distance / time *

velocity  =  110 / 5.5

velocity =  20 m/s

xxMikexx [17]3 years ago
7 0

Answer:

V= 20m/s

Explanation:

velocity= distance/time

V= d/s

= 110m/5.5 seconds

= 20m/s

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In an arcade game a 0.135 kg disk is shot across a frictionless horizontal surface by compressing it against a spring and releas
ioda

Answer:

v=2.42m/s

Explanation:

We use the energy conservation theorem in order to solve the problem. The energy when the spring is compressed is equal at the energy when the disk leaves the spring:

E_{initial}=E{final}\\E_{k-initial}+E_{p-initial}=E_{k-final}+E_{p-final}\\0+\frac{1}{2}kx^2=\frac{1}{2}mv^2+0

At the beginning the initial energy is totally potential, energy linked to the compressed spring. At the end the energy is totally kinetics

We solve the equation in order to find the speed.

k=162 N/m

x=7 cm=0.07m

m=0.135 kg

v=x*\sqrt{k/m}=0.07*\sqrt{162/0.135}=2.42m/s

6 0
3 years ago
A mass of 2.1 kg the ball leaves her hand with the speed of 30 mass find the energy of the ball
snow_lady [41]
Ke= 1/2 x m x v^2
Ke= 1/2 x 2.1 x 30^2
Energy = 945 J
8 0
3 years ago
The modern periodic law, according to Moseley, classifies elements based on arranging elements in ___ order
Daniel [21]
D because it makes sense
4 0
3 years ago
Read 2 more answers
The force that accelerates objects towards earth
Anastasy [175]

The answer is Gravity.

8 0
3 years ago
Read 2 more answers
The moon Ariel orbits Uranus at a distance of 1.91 x 108 m once every 2.52 days. Use that data to calculate the mass of Uranus.
PIT_PIT [208]

Mu = 8.66 × 10^25 kg

Explanation:

centripetal force = gravitational force

m \frac{ {v}^{2} }{r}  = (grav.const) \frac{m \times mu}{ {r}^{2} }

where

m = mass of moon Ariel

mu = mass of Uranus

r = radius of Ariel's orbit

v = Ariel's velocity around Uranus

To find the velocity, we need to find the circumference of the no orbit and then divide it by the period (2.52 days):

circumference = 2πr = 2π×(1.91 × 10^8 m)

= 1.2 × 10^9 m

period = 2.52 days × (24 h/1 day)×(3600 s/1 hr)

= 2.18 × 10^5 s

v = (1.2 × 10^9 m)/(2.18 × 10^5 s)

= 5.5 × 10^3 m/s

(5.5 × 10^3 m/s)^2/(1.91 × 10^8 m) = (6.67 × 10^-11 m^3/kg-s^2)Mu/(1.91 × 10^8 m)^2

Solving Mu,

Mu = 8.66 × 10^25 kg

4 0
3 years ago
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