Answer:
Explanation:
Relation between energy and momentum is as follows .
E = h c / λ
E / c = h / λ
h /λ = momentum of a photon
momentum of a photon = E /c
= 11 x 10³ / 3 x 10⁸
= 3.67 x 10⁻⁵
In 4 days no of photon
= 4 x 24 x 60 x 60 = 345600 .
momentum of photon released
3.67 x 10⁻⁵ x 345600 .
= 12.68 kg m/s
This momentum will be imparted to spaceship .
12.68 = mv
12 .68 = 1300 x v
v = .00975 m /s
= 9.75 mm /s
Incandescent light bulbs consist of an air-tight glass enclosure (the envelope, or bulb) with a filament of tungsten wire inside the bulb, through which an electric current is passed. Contact wires and a base with two (or more) conductors provide electrical connections to the filament.
Most countries besides the USA use the metric system also known as S.I (system internationale) as a system of measurement...
To solve the problem, use Kepler's 3rd law :
T² = 4π²r³ / GM
Solved for r :
r = [GMT² / 4π²]⅓
but first covert 6.00 years to seconds :
6.00years = 6.00years(365days/year)(24.0hours/day)(6...
= 1.89 x 10^8s
The radius of the orbit then is :
r = [(6.67 x 10^-11N∙m²/kg²)(1.99 x 10^30kg)(1.89 x 10^8s)² / 4π²]⅓
= 6.23 x 10^11m
