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wel
4 years ago
10

What volume of 0.200 M H2SO* will be needed to neutralize 50.00 mL of 0.178 MNaOH?

Chemistry
1 answer:
mixas84 [53]4 years ago
7 0

Answer:

10.00 mL

Explanation:

Please, do not forget to write the dot and 2 of Zeros after the number 10 in the answer!

Please see the step-by-step solution in the picture attached below.

Hope this answer can help you. Have a nice day!

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How many grams are there in 1.1 x 1027 molecules of water (H2O)?
Nezavi [6.7K]

Answer:

C) 3.3 x 104 grams

Explanation:

1 mole of water contains 6.02 × 10^23 atoms

1.1 × 10^27 atoms will contain;

1.1 × 10^27 ÷ 6.02 × 10^23

= 0.1827 × 10^( 27 - 23)

= 0.1827 × 10^(4)

= 1.827 × 10³ moles of water.

To convert mole to mass in grams, we use the formula;

mole (n) = mass (m) ÷ molar mass (MM)

Molar mas of water (H2O) = 1(2) of H + 16 of O = 18g/mol

mole = mass/molar mass

1.827 × 10³ = mass / 18

mass = 1.827 × 10³ × 18

mass = 32.886 × 10³

mass = 3.286 × 10⁴

mass = 3.3 × 10⁴ grams

6 0
3 years ago
2Al + 6HCl → 2AlCl3 + 3H2<br> If 85.0 grams of HCl react, how many moles of H2 are produced?
Murrr4er [49]

Answer:

1.17 mol

Explanation:

Step 1: Write the balanced equation

2 Al + 6 HCl → 2 AlCl₃ + 3 H₂

Step 2: Calculate the moles corresponding to 85.0 g of HCl

The molar mass of HCl is 36.46 g/mol.

85.0 g × 1 mol/36.46 g = 2.33 mol

Step 3: Calculate the number of moles of H₂ produced from 2.33 moles of HCl

The molar ratio of HCl to H₂ is 6:3.

2.33 mol HCl × 3 mol H₂/6 mol H₂ = 1.17 mol H₂

8 0
3 years ago
What is something that has mass and takes up space
Leni [432]
Humans.
Humans have mass and take up space. :)

Hope this helps!
5 0
3 years ago
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What is the strongest type of van der Waals force that exists between molecules of ammonia, NH3?
Marianna [84]
It is hydrogen bond(as well as fh, and h2o), intermolecular force.
6 0
3 years ago
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Which of the following is a substance that is found between the cell membrane and the nucleus, which primarily consists of water
VladimirAG [237]
The answer is B, cytoplasm
3 0
4 years ago
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