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wel
4 years ago
10

What volume of 0.200 M H2SO* will be needed to neutralize 50.00 mL of 0.178 MNaOH?

Chemistry
1 answer:
mixas84 [53]4 years ago
7 0

Answer:

10.00 mL

Explanation:

Please, do not forget to write the dot and 2 of Zeros after the number 10 in the answer!

Please see the step-by-step solution in the picture attached below.

Hope this answer can help you. Have a nice day!

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2Al + 3H2SO4 -> Al2(SO4)3 + 3H2How many grams of aluminum sulfate would be formed if 250g H2SO4 completely reacted with alumi
bazaltina [42]

Answer:

290.82g

Explanation:

The equation for the reaction is given below:

2Al + 3H2SO4 -> Al2(SO4)3 + 3H2 now, let us obtain the masses of H2SO4 and Al2(SO4)3 from the balanced equation. This is illustrated below:

Molar Mass of H2SO4 = (2x1) + 32 + (16x4) = 2 + 32 +64 = 98g/mol

Mass of H2SO4 from the balanced equation = 3 x 98 = 294g

Molar Mass of Al2(SO4)3 = (2x27) + 3[32 + (16x4)]

= 54 + 3[32 + 64]

= 54 + 3[96] = 54 + 288 = 342g

Now, we can obtain the mass of aluminium sulphate formed by doing the following:

From the equation above:

294g of H2SO4 produced 342g of Al2(SO4)3.

Therefore, 250g of H2SO4 will produce = (250 x 342)/294 = 290.82g of Al(SO4)3

Therefore, 290.82g of aluminium sulphate (Al(SO4)3) is formed.

7 0
3 years ago
In general, what is the effect of increased temperature on the solubility of a gas?
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Answer:

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Explanation:

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In formation of a Type II Binary Compound, the metal atom present is<span> NOT</span> found in either Group 1 or Group 2 on the periodic table.  For the choices, Ba is under Group 2 on the periodic table, which makes it the atom not involved in formation of type II compounds. The answer is B.
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