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Tanzania [10]
3 years ago
5

Rewrite 76.00 to have 1 sig fig.

Chemistry
1 answer:
Luba_88 [7]3 years ago
4 0

Answer:

76.00

sig fig:4

decmials:2

scientific notation:7.600 x 10 1

words: seventy-six

p.s that one is on the right top side of ten

Explanation:

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How do you determine valence electrons of a metal? A non Metal?
Harlamova29_29 [7]

Answer:

Check the electronic configuration of elements.

Explanation:

▪Valence electrons are the elwctrons present in the outermost shell of any element.

For example,

Electronic Configuration of Sodium = 2,8,1

Here , Sodium has 1 valence electrons.

▪Valency of an element is the total no. of electrons to be gained/losed in order to achieve duplet/octate state.

For example,

Electronic configuration of Sodium = 2,8,1

Sodium can achieve octate state either by losing 1 electron or gaining 7 electrons. But losing 1 electron is eay than gaining 7 electrons. So Valency of Sodium = +1

☆Metals have 1 or 2 or 3 valence electrons.

☆Non metals have 4 or 5 or 6 or 7 valence electrons.

☆Noble gases tend to stay in duplet/octate state i.e they have 2 or 8 valence electrons.

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3 years ago
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Answer:

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Explanation:

7 0
3 years ago
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Determine the empirical and molecular formula for chrysotile asbestos. Chrysotile has the following percent composition: 28.03%
nlexa [21]

<u>Answer:</u> The empirical and molecular formula of chrysotile is Mg_3Si_2H_3O_4 and Mg_6Si_4H_6O_{16}

<u>Explanation:</u>

We are given:

Percentage of Mg = 28.03 %

Percentage of Si = 21.60 %

Percentage of H = 1.16 %

Percentage of O = 49.21 %

Let the mass of compound be 100 g. So, percentages given are taken as mass.

Mass of Mg = 28.03 g

Mass of Si = 21.60 g

Mass of H = 1.16 g

Mass of O = 49.21 g

To formulate the empirical formula, we need to follow some steps:

  • <u>Step 1:</u> Converting the given masses into moles.

Moles of Magnesium = \frac{\text{Given mass of Magnesium}}{\text{Molar mass of Magnesium}}=\frac{28.03g}{24g/mole}=1.17moles

Moles of Silicon = \frac{\text{Given mass of Silicon}}{\text{Molar mass of Silicon}}=\frac{21.06g}{28g/mole}=0.752moles

Moles of Hydrogen = \frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{1.16g}{1g/mole}=1.16moles

Moles of Oxygen = \frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{49.21g}{16g/mole}=3.07moles

  • <u>Step 2:</u> Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.752 moles.

For Magnesium = \frac{1.17}{0.752}=1.5

For Silicon = \frac{0.752}{0.752}=1

For Hydrogen = \frac{1.16}{0.752}=1.5

For Oxygen = \frac{3.07}{0.485}=4.08\approx 4

To convert the mole ratios into whole numbers, we multiply individual mole ratios by 2

Mole ratio of Magnesium = (2 × 1.5) = 3

Mole ratio of Silicon = (2 × 1) = 2

Mole ratio of Hydrogen = (2 × 1.5) = 3

Mole ratio of Oxygen = (2 × 4) = 8

  • <u>Step 3:</u> Taking the mole ratio as their subscripts.

The ratio of Mg : Si : H : O = 3 : 2 : 3 : 8

The empirical formula for the given compound is Mg_3Si_2H_3O_8

For determining the molecular formula, we need to determine the valency which is multiplied by each element to get the molecular formula.

The equation used to calculate the valency is :

n=\frac{\text{Molecular mass}}{\text{Empirical mass}}

We are given:

Mass of molecular formula = 520.8 g/mol

Mass of empirical formula = [(24 × 3) + (28 × 2) + (1 × 3) + (16 × 8)] = 259 g/mol

Putting values in above equation, we get:

n=\frac{520.8g/mol}{259g/mol}=2

Multiplying this valency by the subscript of every element of empirical formula, we get:

Mg_{(3\times 2)}Si_{(2\times 2)}H_{(3\times 2)}O_{(8\times 2)}=Mg_6Si_4H_6O_{16}

Hence, the empirical and molecular formula of chrysotile is Mg_3Si_2H_3O_4 and Mg_6Si_4H_6O_{16}

5 0
3 years ago
How many electrons are in p orbitals in Si (Silicon)?
insens350 [35]

Answer:

6 electrons

Explanation:

The p orbital can hold up to six electrons. We'll put six in the 2p orbital and then put the next two electrons in the 3s.

8 0
3 years ago
A balloon is filled with 2000 mL of air at a pressure of 2 atm. What is the volume of the balloon if the pressure is
artcher [175]

Answer:

800mL

Explanation:

Using Boyle's law which states that the volume of a given mass of gas is inversely proportional to the pressure, provided temperature remains constant

P1V1= P2V2

P1 = 2 atm, V1 = 2000mL ,

P2 = 5atm , V2 = ?

2 × 2000 = 5 × V2

Divide both sides by 5

V2 = 4000 ÷ 5

V2 = 800mL

I hope this was helpful, please mark as brainliest

6 0
3 years ago
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