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Tanzania [10]
3 years ago
5

Rewrite 76.00 to have 1 sig fig.

Chemistry
1 answer:
Luba_88 [7]3 years ago
4 0

Answer:

76.00

sig fig:4

decmials:2

scientific notation:7.600 x 10 1

words: seventy-six

p.s that one is on the right top side of ten

Explanation:

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The Best Answer would be B but the correct answer is A+B --> AB

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Which of the following is a unit of length? O A. A liter O B. A kilogram C. A meter O D. A degree​
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2 years ago
When 136g of glycine are dissolved in of a certain mystery liquid , the freezing point of the solution is lower than the freezin
loris [4]

The given question is incomplete. The complete question is:

When 136 g of glycine are dissolved in 950 g of a certain mystery liquid X, the freezing point of the solution is 8.2C lower than the freezing point of pure X. On the other hand, when 136 g of sodium chloride are dissolved in the same mass of X, the freezing point of the solution is 20.0C lower than the freezing point of pure X. Calculate the van't Hoff factor for sodium chloride in X.

Answer: The vant hoff factor for sodium chloride in X is 1.9

Explanation:

Depression in freezing point is given by:

\Delta T_f=i\times K_f\times m

\Delta T_f=T_f^0-T_f=8.2^0C = Depression in freezing point

K_f = freezing point constant

i = vant hoff factor = 1 ( for non electrolyte)

m= molality =\frac{136g\times 1000}{950g\times 75.07g/mol}=1.9

8.2^0C=1\times K_f\times 1.9

K_f=4.32^0C/m

Now Depression in freezing point for sodium chloride is given by:

\Delta T_f=i\times K_f\times m

\Delta T_f=20.0^0C = Depression in freezing point

K_f = freezing point constant  

m= molality = \frac{136g\times 1000}{950g\times 58.5g/mol}=2.45

20.0^0C=i\times 4.32^0C\times 2.45

i=1.9

Thus vant hoff factor for sodium chloride in X is 1.9

3 0
2 years ago
In a chemical equation, what do the coefficients indicate?
Mekhanik [1.2K]
In a chemical equation coefficients indicate the number of molecules/atoms involved in the reaction.
6 0
3 years ago
Read 2 more answers
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