Which elements are most likely to gain an electron when becoming an ion?
1 answer:
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<h3>Answer:</h3>
64 g O₂
<h3>General Formulas and Concepts:</h3><u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
- Left to Right
<u>Chemistry</u>
<u>Atomic Structure</u>
- Reading a Periodic Table
<u>Stoichiometry</u>
- Using Dimensional Analysis
<u>Step 1: Define</u>
[RxN - Balanced] CH₄ + 2O₂ → CO₂ + 2H₂O
[Given] 36 g H₂O
[Solve] x g O₂
<u>Step 2: Identify Conversions</u>
[RxN] 2 mol O₂ → 2 mol H₂O
[PT] Molar Mass of O - 16.00 g/mol
[PT] Molar Mas of H - 1.01 g/mol
Molar Mass of O₂ - 2(16.00) = 32.00 g/mol
Molar Mass of H₂O - 2(1.01) + 16.00 = 18.02 g/mol
<u>Step 3: Stoichiometry</u>
- Set up conversion:
- Divide/Multiply [Cancel Units]:
<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 2 sig figs.</em>
63.929 g O₂ ≈ 64 g O₂
Answer: 67.2 moles
Explanation:
According to the given balanced equation, 2 moles of acetylene combine with 5 moles of oxygen
to produce 4 moles of carbon dioxide
.
Thus if 2 moles of acetylene combine with = 5 moles of oxygen
35 moles of acetylene combine with=
moles of oxygen
But as only 84 moles of oxygen are available, acetylene is not a limiting reagent.
5 moles of oxygen reacts with = 2 moles of acetylene
84 moles of oxygen reacts with=
moles of acetylene
Thus Oxygen is the limiting reagent as it limits the formation of products. Acetylene is excess reagent as it is present in excess.
2 moles of acetylene produce= 4 moles of carbon dioxide
.
33.6 moles of acetylene produce=
moles of of carbon dioxide
.
This is Bohrs model for potassium
