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lisabon 2012 [21]
3 years ago
6

The element oxegyn, represented by 01, is classified as​

Chemistry
1 answer:
Mashutka [201]3 years ago
7 0

Answer:

It is classified as a pure substance

Explanation:

Oxygen is a gas present in the atmosphere in the pure elemental form.

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Brainiest plsss helpp
djyliett [7]

Answer:

b 13kg/m³ is the answer to this question

8 0
3 years ago
Read 2 more answers
Which of the following is correct for adsorption theory of Heterogeneous catalysis? Statement-I : This theory explains why the c
Ostrovityanka [42]

Answer:

The correct answer is - Statement I is true, Statement-II is false.

Explanation:

3 0
3 years ago
Explain how you would convert the moles of a compound to the made (grams) of the same compound<br>​
Oduvanchick [21]

Answer:

see notes below

Explanation:

The mole is the mass of substance containing 1 Avogadro's Number of particles. That is, 1 mole substance = 1 formula weight. For elements, 1 mole weight is equal to the atomic weight expressed as grams. For molecules, 1 mole weight is equal to the molecular weight expressed as grams.

1 mole = 1 formula weight

<u>Moles to Grams and Grams to Moles</u>

Grams => Moles

Given grams, moles = mass given / formula weight

*Ask the question => How many formula weights are there in the given mass? => Results is always moles.

Moles => Grams

Given moles,  grams = moles given X formula weight

*Summary

Grams to Moles => divide by formula weight

Moles to Grams => multiply by formula weight

3 0
3 years ago
Calculate ΔH for the reaction: C(graphite) + 2H 2(g) + 1/2 O 2(g) =&gt; CH 3OH(l) Using the following information: C(graphite) +
Alika [10]

Answer:

\Delta H for the given reaction is -238.7 kJ

Explanation:

The given reaction can be written as summation of three elementary steps such as:

C(graphite)+O_{2}(g)\rightarrow CO_{2}(g) \Delta H_{1}= -393.5 kJ

2H_{2}(g)+O_{2}(g)\rightarrow 2H_{2}O(l) \Delta H_{2}= (2\times -285.8)kJ

CO_{2}(g)+2H_{2}O(l)\rightarrow CH_{3}OH(l)+\frac{3}{2}O_{2}(g)  \Delta H_{3}= 726.4 kJ

---------------------------------------------------------------------------------------------------

C(graphite)+2H_{2}(g)+\frac{1}{2}O_{2}(g)\rightarrow CH_{3}OH(l)

\Delta H=\Delta H_{1}+\Delta H_{2}+\Delta H_{3}=-238.7 kJ

4 0
3 years ago
What is the molecular formula for C5H7 if its molar mass is 536 g/mol?
hodyreva [135]

Answer:

(C5H7)8

Explanation:

It's empirical formula is given as; C5H7

Molar mass of carbon(C) = 12 g/mol

Molar mass of hydrogen(H) = 1 g/mol

We are told that it's molar mass is 536 g/mol.

To find the molecular formula;

Molecular formula = n × empirical formula

Thus;

n = 536/((12 × 5) + (1 × 7))

n = 8

Thus;

Molecular formula = (C5H7)8

8 0
3 years ago
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