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siniylev [52]
3 years ago
14

What does acceleration mean?

Physics
1 answer:
max2010maxim [7]3 years ago
8 0
Acceleration occurs when velocities change.velocity changes either because the speed changes or the direction change.
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While online last week, you saw the following advertisement:
Karolina [17]
No scientific testing has been made to check for ion transfer, and the claims are purely empirical. Also, nine out of ten people is hardly a representative sample, and the people can claim whatever they want since "feeling" is subjective. This is most likely a pseudoscientific claim, made to sound legitimate to consumers. The best answer is choice D.
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3 years ago
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The 45-g arrow is launched so that it hits and embeds in a 1.40 kg block. The block hangs from strings. After the arrow joins th
worty [1.4K]

Question: How fast was the arrow moving before it joined the block?

Answer:

The arrow was moving at 15.9 m/s.

Explanation:

The law of conservation of energy says that the kinetic energy of the arrow must be converted into the potential energy of the block and arrow after it they join:

\dfrac{1}{2}m_av^2 = (m_b+m_a)\Delta Hg

where m_a is the mass of the arrow, m_b is the mass of the block, \Delta H of the change in height of the block after the collision, and v is the velocity of the arrow before it hit the block.

Solving for the velocity v, we get:

$v = \sqrt{\frac{2(m_b+m_a)\Delta Hg}{m_a} } $

and we put in the numerical values

m_a = 0.045kg,

m_b = 1.40kg,

\Delta H = 0.4m,

g= 9.8m/s^2

and simplify to get:

\boxed{ v= 15.9m/s}

The arrow was moving at 15.9 m/s

6 0
3 years ago
Any person for the job he applied Force moment or torque​
VLD [36.1K]

Answer:

i think torque is the answer not confirmed

7 0
2 years ago
A miner of mass 90kg travels down a slide calculate the potential energy of the miner when he moves15m vertically downwards
Lena [83]
Answer:

Gravitational Potential Energy = mgh

Explanation:

As the miner moves down, the GPE changes because the height changes.

Gravitational Potential Energy = mgh


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3 years ago
A 0.2-kg steel ball is dropped straight down onto a hard, horizontal floor and bounces straight up. The ball's speed just before
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Answer:

Explanation:

Given

mass of steel ball m=0.2\ kg

initial speed of ball u=10\ m/s

Final speed of ball v=-10\ m/s (in upward direction)

Impulse imparted is given by change in the momentum of object

therefore impulse J is given by

J=\Delta P

\Delta P=m(v-u)

\Delta P=0.2(-10-10)

\Delta =-4\ N-s

so magnitude of Impulse =4 N-s

7 0
2 years ago
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