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11Alexandr11 [23.1K]
3 years ago
8

How many molecules are in 3 moles of CO2?

Chemistry
2 answers:
Alenkinab [10]3 years ago
3 0

Answer:

<h2>1.806 × 10²⁴</h2>

Explanation:

The number of molecules can be found by using the formula

N = n × L

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

N = 3 × 6.02 × 10²³

We have the final answer as

<h3>1.806 × 10²⁴</h3>

Hope this helps you

Dafna1 [17]3 years ago
3 0

Answer: OB. 1.806 x 1024

Explanation:

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<h3>What is chemical bonding?</h3>

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Explanation:

The given data is as follows.

Air is at 75^{o}F and 14.6 psia.

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              r_{H} = \frac{\text{free flow area}}{\text{wet perimeter}}

                          = \frac{2 \times 1}{2(1) + 2(2)}

                          = \frac{1}{3} ft

Formula for equivalent diameter is as follows.

                     D_{eq} = 4 \times r_{H}

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                                    = \frac{4}{3} ft

(b)    Formula for velocity floe is as follows.

                         Q = VA

                     V = \frac{Q}{A}

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(c)   Formula to calculate Reynold's number is as follows.

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                   = 53742.66 hr/min  

As 1 hr = 10 min. So, 53742.66 hr/min \times \frac{60 min}{1 hr}

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              \frac{\Delta P}{L} = \frac{4f \rho V^{2}}{2Dg_{c}}

Putting the given values into the above formula as follows.

               \frac{\Delta P}{L} = \frac{4f \rho V^{2}}{2Dg_{c}}

                      = \frac{4 \times 0.00015 \times 100 \times 0.0744 \times (24000)^{2}}{2 \times \frac{4}{3} \times {4}{3}}

                      = 6.238 lb/ft^{2}

5 0
3 years ago
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