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Papessa [141]
3 years ago
12

suppose that a particle at rest with mass m decays into a photon and another particle with mass m/2 , which recoilds in a direct

ion opposite to the photon. Using the conservation of energy and momentum find the momentum of the recoiling particle
Physics
1 answer:
Nady [450]3 years ago
5 0

Answer:

p_r=\frac{h}{\lambda}

Explanation:

To find the momentum of the recoiling particle you can use the momentum formula for a photon:

p=\frac{h}{\lambda}

before the decay the momentum is zero. Hence, after the decay the momentum of the photon plus the momentum of the recoiling particle must be zero:

p_a=p_b\\\\\frac{h}{\lambda}-\frac{m}{2}v=0\\\\p_r=\frac{m}{2}v=\frac{h}{\lambda}

where pr is the momentum of the recoiling particle.

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The engine in an imaginary sports car can provide constant power to the wheels over a range of speeds from 0 to 70 miles per hou
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Answer:

t=5.3687\ s  is the time taken by the car to accelerate the desired range of the speed from zero at full power.

Explanation:

Given:

Range of speed during which constant power is supplied to the wheels by the car is 0\ mph\ to\ 70\ mph.

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Now the acceleration of the car:

a=\frac{v_f-v_i}{t}

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Now using the equation of motion:

u_f=u_i+a.t

64=0+11.921\times t

t=5.3687\ s is the time taken by the car to accelerate the desired range of the speed from zero at full power.

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What is the least amount of time required for a given point on this wave to move from y = 0 to y = 12cm?
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Time t = ?

<span>When wave is moving from y = 0  to y =12 cm</span>

By using the formula,

y = 15cos [(π/12) t)] = 0,

cos [(π/12) t)] = 0 = cos (π/2), so, 

(π/12)t = π/2,

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t = 12/2

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An electric motor rotating a workshop grinding wheel at 1.00 × 10² rev/min is switched off. Assume the wheel has a constant nega
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An electric engine turning a workshop sanding rotation at 1.00 × 10² rev/min is switched off. Take the wheel includes a regular negative angular acceleration of volume 2.00 rad/s². 5.25 moments long it takes the grinding rotation to control.

<h3>What is negative angular acceleration?</h3>
  • A particle that has a negative angular velocity rotates counterclockwise.
  • Negative angular acceleration () is a "push" that is hence counterclockwise.
  • The body will speed up or slow down depending on whether and have the same sign (and eventually go in reverse).
  • For instance, when an object rotating counterclockwise slows down, acceleration would be negative.
  • If a rotating body's angular speed is seen to grow in a clockwise direction and decrease in a counterclockwise direction, it is given a negative sign.
  • It is known that a change in the linear acceleration correlates to a change in the linear velocity.

Let t be the time taken to stop.

ω = 0 rad/s

Use the first equation of motion for rotational motion

ω = ωo + α t

0 = 10.5 - 2 x t

t = 5.25 second

To learn more about angular acceleration, refer to:

brainly.com/question/21278452

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