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Papessa [141]
3 years ago
12

suppose that a particle at rest with mass m decays into a photon and another particle with mass m/2 , which recoilds in a direct

ion opposite to the photon. Using the conservation of energy and momentum find the momentum of the recoiling particle
Physics
1 answer:
Nady [450]3 years ago
5 0

Answer:

p_r=\frac{h}{\lambda}

Explanation:

To find the momentum of the recoiling particle you can use the momentum formula for a photon:

p=\frac{h}{\lambda}

before the decay the momentum is zero. Hence, after the decay the momentum of the photon plus the momentum of the recoiling particle must be zero:

p_a=p_b\\\\\frac{h}{\lambda}-\frac{m}{2}v=0\\\\p_r=\frac{m}{2}v=\frac{h}{\lambda}

where pr is the momentum of the recoiling particle.

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The height above the ground from where the skier start is 11.5 m.

<h3>Conservation of energy</h3>

The height above the ground from where the skier start is determined by applying the principle of conservation of energy as shown below;

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8 0
2 years ago
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Explanation:

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So you do

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3 years ago
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Answer:

Time period of the osculation will be 2.1371 sec

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As there is additional streching of spring by 3 cm

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