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sergij07 [2.7K]
3 years ago
13

The radios of the moon is aproximately 1,350,000m)

Physics
1 answer:
viktelen [127]3 years ago
6 0

Answer:

135,000,000

Explanation:

mafs

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A boy swings a ball on a string at constant speed in a circle that has a circumference equal to 6 m. What is the work done on th
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Answer:

0 J

Explanation:

From the diagram below; we would notice that the Force (F) = Tension (T)

Also the angle θ adjacent to the perpendicular line = 90 °

The Workdone W = F. d

W = Fd cos θ

W = Fd cos 90°

W = Fd (0)

W = 0 J

Hence the force is perpendicular to the direction of displacement and the net work done in a circular motion in one complete revolution is = 0

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a body initially at rest, starts moving with a constant acceleration of 2ms-2 .calculate the velocity acquired and the distance
Marta_Voda [28]

a) 10 m/s

b) 25 m

Explanation:

a)

The body is moving with a constant acceleration, therefore we can solve the problem by using the following suvat equation:

v=u+at

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u is the initial velocity

v is the final velocity

a is the acceleration

t is the time

For the body in this problem:

u = 0 (the body starts from rest)

a=2 m/s^2 is the acceleration

t = 5 s is the time

So, the final velocity is

v=0+(2)(5)=10 m/s

b)

In this second part, we want to calculate the distance travelled by the body.

We can do it by using another suvat equation:

v^2-u^2=2as

where

u is the initial velocity

v is the final velocity

a is the acceleration

s is the distance travelled

Here we have

u = 0 (the body starts from rest)

a=2 m/s^2 is the acceleration

v = 10 m/s is the final velocity

Solving for s,

s=\frac{10^2-0^2}{2(2)}=25 m

3 0
3 years ago
Someone help me with this ASPA!!!
Irina18 [472]
A delta is formed at the mouth of a river as sediment is carried downstream
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3 years ago
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An electric motor operates a pump that irri-
PolarNik [594]

Answer:

a. 5A

b. 39.60%

Explanation:

The computation is shown below:

a. The current does it draw is

= v ÷ R

= 110v  ÷ 22

= 5A

b. Now the efficiency of the motor is

n = mgh ÷ vlt

= (10,000 × 9.8 × 8) ÷ (5 × 3600 × 110)

= 784000 J ÷ 1,980,000

= 39.60%

hence, the above formulas are applied & the same is relevant

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