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strojnjashka [21]
3 years ago
10

Here's a great everyday use of the physics described in Think about what subsequently happens to the ketchup, which is initially

at rest, and use Newtons first law to explain why this technique is so successful this chapter. If you are trying to get keichup out of the bottle, the best way to do it is to turn the bottle upside down and give the bottie a sharp upward smack, forcing the bottle rapidly upward. (Figure 1 The weight of the ketchup will keep it from moving if you give the bottle a sharp upward smack Figure The static friction of the ketchup wil keep it from moving if it isnt too tightly adhered to the sides of the moving bottle of1 The inertia of the ketchup will keep it from moving if it isn't too tightly adhered to the sides of the moving bottle. The kinetic friction of the ketchup will keep it from moving if it isn't too tightly adhered to the sides of the moving bottle
Physics
2 answers:
balandron [24]3 years ago
6 0

Answer:

Explanation:

The inertia of the ketchup will keep it from moving if it isn't too tightly adhered to the sides of the moving bottle.

Andrei [34K]3 years ago
5 0

Answer: "The static friction of the ketchup wil keep it from moving if it isnt too tightly adhered to the sides of the moving bottle"

Explanation:

We want to see why is that the ketchup does not move of the bottom of the bottle when we want to use it.

The options are:

Because of the weight.

Because of the static friction.

Because of the inertia.

Because of the kinetic friction.

First, we can discard weight and inertia, because these two things actually help to get the ketchup out of the bottle.

The remaining options are static friction and kinetic friction:

If the kinetic friction has an effect, it means that the ketchup inside the bottle is moving, so this option can also be discarded.

Then the correct option is static friction, which the ketchup does against the walls of the bottle and keeps it in place.

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Which artist of the northern European Renaissance, shown in this self-portrait, was also a block printer and engraver?
kicyunya [14]
It's very hard to see the self-portrait, so I can't identify him.
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3 years ago
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Calculate the force of a particle with a net charge of 170 coulombs traveling at a speed of 135 meters/second perpendicular to t
amm1812

Answer:

F=1.14N j

Explanation:

The magnitude of the magnetic force over a charge in a constant magnetic field is given by the formula:

|\vec{F}|=|q\vec{v} \ X\ \vec{B}|=qvsin\theta  (|)

In this case v and B vectors are perpendicular between them. Furthermore the direction of the magnetic force is:

-i X k = +j

Finally, by replacing in (1) we obtain:

\vec{F}=(170C)(135\frac{m}{s})(5.0*10^{-5}T)=1.14N\ \hat{j}

hope this helps!

6 0
3 years ago
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A charged object is suspended motionless in the air by the gravitational force pulling it down and an electric force pushing it
Savatey [412]

The charge of the object must be 1.11 \times e^{-5} \text { coulomb }

Answer: Option C

<u>Explanation:</u>

Suppose an electric charge can be represented by the symbol Q. This electric charge generates an electric field; Because Q is the source of the electric field, we call this as source charge. The electric field strength of the source charge can be measured with any other charge anywhere in the area. The test charges used to test the field strength.

Its quantity indicated by the symbol q. In the electric field, q exerts an electric, either attractive or repulsive force. As usual, this force is indicated by the symbol F. The electric field’s magnitude is simply defined as the force per charge (q) on Q.

         Electric field, E=\frac{\text { Force }(F)}{q}

Here, given E = 4500 N/C and F = 0.05 N.

We need to find charge of the object (q)

By substituting the given values, we get

      q=\frac{F}{E}=\frac{0.05 N}{4500 \mathrm{N} / \mathrm{c}}=1.11 \times e^{-5} \text { coulomb }

6 0
3 years ago
What is the net force on a bag pulled down by gravity with a force of 18 newtons and pulled upward by a rope with a force of 18
VARVARA [1.3K]

Answer:

0 N.

Explanation:

Force: This can be defined as the product of mass and the acceleration of the body. The S.I unit of force is Newton (N).

The expression of net force when both force act in the different direction is given as

F' = W-F ........................ Equation 1

Where F' = Net force on the bag, W = gravitational force on the bag, F = Force acting upward on the bag

Given: W = 18 N, F = 18 N.

Substitute into equation 1

F' = 18-18

F' = 0 N.

Hence the net force = 0 N.

4 0
3 years ago
Determine the gain in the potential energy when a 8.0 kg box is raised 17.2 m.
Marysya12 [62]

Answer:

<h2>The answer is 1376 J</h2>

Explanation:

The potential energy of a body can be found by using the formula

PE = mgh

where

m is the mass

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We have the final answer as

<h3>1376 J</h3>

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