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strojnjashka [21]
3 years ago
10

Here's a great everyday use of the physics described in Think about what subsequently happens to the ketchup, which is initially

at rest, and use Newtons first law to explain why this technique is so successful this chapter. If you are trying to get keichup out of the bottle, the best way to do it is to turn the bottle upside down and give the bottie a sharp upward smack, forcing the bottle rapidly upward. (Figure 1 The weight of the ketchup will keep it from moving if you give the bottle a sharp upward smack Figure The static friction of the ketchup wil keep it from moving if it isnt too tightly adhered to the sides of the moving bottle of1 The inertia of the ketchup will keep it from moving if it isn't too tightly adhered to the sides of the moving bottle. The kinetic friction of the ketchup will keep it from moving if it isn't too tightly adhered to the sides of the moving bottle
Physics
2 answers:
balandron [24]3 years ago
6 0

Answer:

Explanation:

The inertia of the ketchup will keep it from moving if it isn't too tightly adhered to the sides of the moving bottle.

Andrei [34K]3 years ago
5 0

Answer: "The static friction of the ketchup wil keep it from moving if it isnt too tightly adhered to the sides of the moving bottle"

Explanation:

We want to see why is that the ketchup does not move of the bottom of the bottle when we want to use it.

The options are:

Because of the weight.

Because of the static friction.

Because of the inertia.

Because of the kinetic friction.

First, we can discard weight and inertia, because these two things actually help to get the ketchup out of the bottle.

The remaining options are static friction and kinetic friction:

If the kinetic friction has an effect, it means that the ketchup inside the bottle is moving, so this option can also be discarded.

Then the correct option is static friction, which the ketchup does against the walls of the bottle and keeps it in place.

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What happens to most of the light waves that strike a clear pane of glass
Marysya12 [62]
It’s C


Because C is a reflection which reflects something such as mirror

Hope this helps! •~•
3 0
3 years ago
Read 2 more answers
Suppose the maximum power delivered by a car's engine results in a force of 16000 N on the car by the road. In the absence of an
joja [24]

Answer:

Approximately 9.7\; \rm m \cdot s^{-2}.

Explanation:

Assuming that there is no other force on this vehicle, the 16000\; \rm N force from the road would be the only force on this vehicle. The net force would then be equal to this 16000\; \rm N\! force. The size of the net force would be 16000\; \rm N\!\!.

Let m denote the mass of this vehicle and let \Sigma F denote the net force on this vehicle.  

By Newton's Second Law of motion, the acceleration of this vehicle would be proportional to the net force on this vehicle. In other words, the acceleration of this vehicle, a, would be:

\begin{aligned}a &= \frac{\Sigma F}{m}\end{aligned}.

For this vehicle, \Sigma F = 16000\; \rm N whereas m = 1650\; \rm kg. The acceleration of this vehicle would be:

\begin{aligned}a &= \frac{16000\; \rm N}{1650\; \rm kg} \\ &= \frac{16000\; \rm kg \cdot m\cdot s^{-2}}{1650\; \rm kg}\\ &\approx 9.7 \; \rm m \cdot s^{-2}\end{aligned}.

8 0
3 years ago
a particle is moving along a circular path having a radius of 4 in such that its position as a function of time is given by thet
ANTONII [103]

Answer:

Explanation:

Given

radius of circular path r=4\ in.

Position is given by

\theta =\cos 2t---1

Differentiate 1  to angular velocity we get

\frac{\mathrm{d} \theta }{\mathrm{d} t}=\omega =-2\sin 2t----2

Differentiate 2 to get angular acceleration

\frac{\mathrm{d} \omega }{\mathrm{d} t}=-2^2\cos 2t ---3

Net acceleration is the vector summation of tangential and centripetal force

a_t=\alpha \times r

a_t=-4\cos 2t\times 4=-16\cos 2t

a_r=\omega ^2\cdot r

a_r=(-2\sin 2t)^2\cdot 4

a_r=16\sin^2(2t)

a_{net}=\sqrt{a_r^2+a_t^2}

a_{net}=\sqrt{(16\sin ^2(2t)+(-16\cos 2t)^2}

a_{net}=\sqrt{256\cos ^2(2t)+256\sin ^4(2t)}                                                    

6 0
3 years ago
There are many interesting applications of our energy density model to the flow of blood in the human circulatory system. One in
qaws [65]

Answer:

Pressure increases due to enlargement

Explanation:

Energy density is just a fancy name for pressure

Pressure is same at the bottom of the cups (same level-Pascal's law)

thus, Air pressure 1 + h1d1g = Air pressure 2 + h2d1g

= Air pressure 3 + (h2-h1)d2g +h1d1g

from the first 2, we get that since h2>h1, AP2<AP1

from the next 2, we get that since d2<d1, AP3>AP2

from first and third, we get that AP1>AP3

thus, finally AP1>AP3>AP2

for fluids flowing in tubes (blood vessel in this case)

P+0.5dv^2 + gh is constant (also called the bernoulli equation

for the same blood vessel, the heights remain same i.e h1=h2

for same flow rate, inc in area decreases the speed at which the blood flows as vA must remain same

hence, P increases due to enlargement

5 0
3 years ago
Read 2 more answers
Which statement about two objects having the same momentum is true?
Reil [10]

Answer:

The product of mass X velocity is the same for both

Explanation:

The momentum of a body is the product of its mass and velocity.

  Momentum  = mass x velocity

Two objects having equal momentum will have the same for the product of their mass and velocity.

  • It is amount of motion a body can produce.
7 0
3 years ago
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