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andrezito [222]
3 years ago
6

A particle moves along a straight line with equation of motion s = f(t), where s is measured in meters and t in seconds. Find th

e velocity and the speed when t = 4. f(t) = 12 + 35 t + 1
Physics
1 answer:
Igoryamba3 years ago
5 0

A particle moves along a straight line with equation of motion s = f(t), where s is measured in meters and t in seconds. Find the velocity and the speed when t = 4. f(t) = 12t² + 35 t + 1

Answer:

Velocity = 131 m/s

Speed = 131 m/s

Explanation:

Equation of motion, s = f(t) = 12t² + 35 t + 1

To get velocity of the particle, let us find the first derivative of s

v (t) = ds/dt = 24t + 35

At t = 4

v(4) = 24(4) + 35

v(4) = 131 m/s

Speed is the magnitude of velocity. Since the velocity is already positive, speed is also 131 m/s

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Answer:

T_2 = 77.5c

Explanation:

From the question we are told that

Temp of first boltsT_1=100

Temp of 2nd bolt T_2=55

Generally the equation showing the relationship between  heat & temperature is given by

  q=cm \triangle T

Generally heat released  by the iron bolt  = heat gained by the iron bolt

Generally solving mathematically

     -(0.45*m* (T_2-100  \textdegree c)) = 0.45*m*(T_2 -55\textdegree c)

     -(T_2-100 \textdegree c)) = (T_2 -55 \textdegree c)

      T_2 +T_2= 100 \textdegree c+55 \textdegree c

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      T_2 = 77.5 \textdegree c

Therefore T_2 = 77.5 \textdegree c is the final temperature inside the container

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3 years ago
How many different types of atoms are present in one molecule of aluminum hydroxide, Al(OH)3?
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Machmer Hall is 400 m North and 180 m West of Witless.
yan [13]

Answer:

The distance from Witless to Machmer is 438.63 m.

Explanation:

Given that,

Machmer Hall is 400 m North and 180 m West of Witless.

We need to calculate the distance

Using Pythagorean theorem

D = \sqrt{(d_{m})^2+(d_{w})^2}

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Hence, The distance from Witless to Machmer is 438.63 m.

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