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sasho [114]
3 years ago
7

Which of the following materials is an insulator against electric current

Physics
2 answers:
Leya [2.2K]3 years ago
8 0

Aluminum foil (I think, it may not be right)

vredina [299]3 years ago
6 0

Answer:

C. a glass pane

Explanation:

I took the quiz, k12 8th grade

best of luck to all... <3

<em>4-29-20</em>

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If you connected 10 of these 12V (10 W) lamps in parallel, to the 12V source, how much current would the source have to supply
Flauer [41]

Answer:

T=8.33A

Explanation:

From the question we are told that:

Number of battery n=10

Voltage sourceE=12V

Lamp PowerP=10W

Generally the equation for Resistance is mathematically given by

 R=\frac{V^2}{P}

 R=\frac{12^2}{10}

 R=14.4ohms

Therefore

 R_{eq}=\frac{14.4}{10}

 R_{eq}=1.44

Generally the equation for Current is mathematically given by

 T=\ffrac{V}{Req}

 T=\frac{12}{1.44}

 T=8.33A

6 0
2 years ago
The Steamboat Geyser in Yellowstone National Park shoots water into the air at 48.0 m/s. How
qwelly [4]

Answer:

The maximum height reached by the water is 117.55 m.

Explanation:

Given;

initial velocity of the water, u = 48 m/s

at maximum height the final velocity will be zero, v = 0

the water is going upwards, i.e in the negative direction of gravity, g = -9.8 m/s².

The maximum height reached by the water is calculated as follows;

v² = u² + 2gh

where;

h is the maximum height reached by the water

0 = u² + 2gh

0 = (48)² + ( 2 x -9.8 x h)

0 = 2304 - 19.6h

19.6h = 2304

h = 2304 / 19.6

h = 117.55 m

Therefore, the maximum height reached by the water is 117.55 m.

7 0
2 years ago
Read 2 more answers
PLEASE HELP!!!!!!! MT TIME FOR MY TEST IS ALMOST OVER!!!
pav-90 [236]

Answer:

50 N

Explanation:

Let the natural length of the spring = L

so

100 = k(40 - L)       (1)

200 = k(60 - L)       (2)

(2)/(1):   2 = (60 - L)/(40 - L)

60 - L = 2(40 - L)

60 - L = 80 - 2L

2L - L = 80 - 60

L = 20

Sub it into (1):

100 = k(40 - 20) = 20k

k = 100/20 = 5 N/in

Now

X = k(30 - L) = 5(30 - 20) = 50 N

3 0
2 years ago
A body has masses of 0.013kg and 0.012kg in oil and water respectively, if the relative density of oil is 0.875, calculate the m
konstantin123 [22]

Answer:

the mass of the body is 0.02 kg.

Explanation:

Given;

relative density of the oil, \gamma _0 = 0.875

mass of the object in oil, M_o = 0.013 kg

mass of the object in water, M_w = 0.012 kg

let the mass of the object in air = M_a

weight of the oil, W_0 = M_a - 0.013

weight of the water, W_w = M_a - 0.012

The relative density of the oil is given as;

\gamma_0 = \frac{density \ of \ oil }{density \ of \ water} = \frac{W_0}{W_w} = \frac{M_a -0.013}{M_a -0.012} \\\\0.875 = \frac{M_a -0.013}{M_a -0.012}\\\\0.875(M_a - 0.012) = M_a - 0.013\\\\0.875M_a - 0.0105 = M_a -0.013\\\\0.875M_a - M_a = 0.0105 - 0.013\\\\-0.125 M_a = -0.0025\\\\M_a = \frac{0.0025}{0.125} \\\\M_a = 0.02 \ kg

Therefore, the mass of the body is 0.02 kg.

6 0
2 years ago
If you had only one match, and entered a dark room containing an oil lamp, some newspaper, and some kindling wood, which would y
alukav5142 [94]
The match
you need to light the match before you can light anything else.

and after the match is lit, maybe light the oil lamp first

7 0
2 years ago
Read 2 more answers
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