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exis [7]
3 years ago
9

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!

Physics
3 answers:
xxMikexx [17]3 years ago
8 0
14-6 =8
8/4= 2m/s per second
Leto [7]3 years ago
6 0

accn=change in vel/time

8/4=2m/s/s

jeka943 years ago
4 0

accn=change in vel/time

8/4=2m/s/s

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Kipish [7]

Answer:

okay

Explanation:

6 0
3 years ago
Read 2 more answers
a man checked himself into seattle hospital. he didnt know who he was and had no idea how he got to seattle. the hospital staff
8090 [49]

Amnesia would be the answer

7 0
3 years ago
Read 2 more answers
A 5.31 kg object is swung in a vertical circular path on a string 2.99 m long. The acceleration of gravity is 9.8 m/s 2 . If the
11111nata11111 [884]

Answer:

T = 120.3 N

Explanation:

Since, the tension in the rope is acting against both the centripetal force and the weight of the stone. As both act downward towards center of the circle and tension acts towards point of support that is upward. So, tension will be equal to the sum of centripetal force and weight of the stone:

Tension = Centripetal Force + Weight of Stone

T = mv²/r + mg

where,

m = mass of stone = 5.31 kg

r = radius of circle = length of string = 2.99 m

g = 9.8 m/s²

Therefore,

T = (5.31 kg)(6.2 m/s)²/(2.99 m) + (5.31 kg)(9.8 m/s²)

T = 68.27 N + 52.03 N

<u>T = 120.3 N</u>

4 0
3 years ago
A 1000-kg whale swims horizontally to the right at a speed of 6.0 m/s. It suddenly collides directly with a stationary seal of m
anzhelika [568]

Answer:

Momentum after collision will be 6000 kgm/sec

Explanation:

We have given mass of the whale = 1000

Initial velocity v = 6 m/sec

It collides with other mass of 200 kg which is at stationary

Initial momentum of the whale = 1000×6 = 6000 kgm/sec

We have to find the momentum after collision

From conservation of momentum

Initial momentum = final momentum

So final momentum = 6000 kgm/sec

5 0
3 years ago
6. Two light bulbs are designed for use at 120 V and are rated at 75 W and 150 W. Which light bulb has the greater filament resi
Nonamiya [84]

\\ \bull\tt\longrightarrow P=\dfrac{V^2}{R}

  • P is power
  • R is resistance

\\ \bull\tt\longrightarrow R=\dfrac{V^2}{P}

Hence

\\ \bull\tt\longrightarrow R\propto V

\\ \bull\tt\longrightarrow R\propto \dfrac{1}{P}

  • Therefore if power is low then resistance will be high.

The first bulb has less power hence it has greater filament resistance.

5 0
3 years ago
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