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2 years ago

Gravity attracts an object to

Physics

1 answer:

tamaranim1 [39]2 years ago

5 0

Answer:

Explanation:

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How many electrons make up a charge of - 30.0 μc?

Ymorist [56]

Each electron has a charge of

$q=-1.6 \cdot 10^{-19}C$

In this problem, the total charge is

$Q=-30.0 \mu C=-30.0 \cdot 10^{-6} C$

Therefore, the number of electrons contained in this total charge will be given by the total charge divided by the charge of a single electron:

$N=\frac{Q}{q}=\frac{-30.0 \cdot 10^{-6} C}{-1.6 \cdot 10^{-19} C}=1.88 \cdot 10^{14}$

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3 years ago

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Estimate the inductance L of a coil that is 12 cm long, made of about 235 copper-wire turns and a diameter of about 1.7 cm. Show

ANTONII [103]

Answer:

Inductance as calculated is 13.12 mH

Solution:

As per the question:

Length of the coil, l = 12 cm = 0.12 m

Diameter, d = 1.7 cm = 0.017 m

No. of turns, N = 235

Now,

Area of cross-section of the wire, A = $\frac{\pi d^{2}}{4} = \frac{\pi \times 0.017^{2}}{4} = 2.269\times 10^{- 4}\ m^{2}$

We know that the inductance of the coil is given by the formula:

$L = \frac{mu_{o}AN^{2}}{l} = \frac{4\pi \times 10^{- 7}\times 2.269\times 10^{- 4}\times 235^{2}}{0.12} = 1.312\times 10^{- 4}\ H = 13.12\ mH$

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2 years ago

Which of the following statements is true? A. X-rays have longer wavelengths than microwaves. B. Radio waves have shorter wavele

3241004551 [841]

D is correct, Gamma rays have the shortest wavelength.

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2 years ago

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Answer:

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2 years ago

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Unpolarized light with intensity I0I0I_0 is incident on an ideal polarizing filter. The emerging light strikes a second ideal po

zvonat [6]

Answer:

$0.293I_0$

Explanation:

When the unpolarized light passes through the first polarizer, only the component of the light parallel to the axis of the polarizer passes through.

Therefore, after the first polarizer, the intensity of light passing through it is halved, so the intensity after the first polarizer is:

$I_1=\frac{I_0}{2}$

Then, the light passes through the second polarizer. In this case, the intensity of the light passing through the 2nd polarizer is given by Malus' law:

$I_2=I_1 cos^2 \theta$