Answer:
Heat of vaporization will be 22.59 j
Explanation:
We have given mass m = 10 gram
And heat of vaporization L = 2.259 J/gram
We have to find the heat required to vaporize 10 gram mass
We know that heat of vaporization is given by
, here m is mass and L is latent heat of vaporization.
So heat of vaporization Q will be = 10×2.259 = 22.59 J
Answer:
Atherosclerosis is a disease of the arteries characterized by the deposition of plaques of fatty material on the inner walls.
Explanation:
Atherosclerosis often has no symptoms until a plaque ruptures or the buildup is severe enough to block blood flow.
Answer:
(a) ![L=2.6742\times 10^{40}\, kg.m^2.s^{-1}](https://tex.z-dn.net/?f=L%3D2.6742%5Ctimes%2010%5E%7B40%7D%5C%2C%20kg.m%5E2.s%5E%7B-1%7D)
(b) ![L_s=7.07 \times 10^{23} \, kg.m^2.s^{-1}](https://tex.z-dn.net/?f=L_s%3D7.07%20%5Ctimes%2010%5E%7B23%7D%20%5C%2C%20kg.m%5E2.s%5E%7B-1%7D)
Explanation:
<u>For Earth we have:</u>
- mass of earth,
![m_E=5.97\times 10^{24}\, kg](https://tex.z-dn.net/?f=%20m_E%3D5.97%5Ctimes%2010%5E%7B24%7D%5C%2C%20kg)
- radius of earth,
![R_E=6.38\times 10^6m](https://tex.z-dn.net/?f=%20R_E%3D6.38%5Ctimes%2010%5E6m)
- orbital radius,
![r=1.5 \times 10^{11}m](https://tex.z-dn.net/?f=r%3D1.5%20%5Ctimes%2010%5E%7B11%7Dm)
- period of rotation,
![t_{rot}=24h=86400\, s](https://tex.z-dn.net/?f=t_%7Brot%7D%3D24h%3D86400%5C%2C%20s)
- period of revolution,
![t_{rev}= 1 yr=3.156\times 10^7 s](https://tex.z-dn.net/?f=t_%7Brev%7D%3D%201%20yr%3D3.156%5Ctimes%2010%5E7%20s)
(a)
Angular momentum, ![L=?](https://tex.z-dn.net/?f=L%3D%3F)
∵
...............................(1)
For a particle of mass m moving in a circular path at a distance r from the axis,
![I=m.r^2](https://tex.z-dn.net/?f=I%3Dm.r%5E2)
& ![v=r.\omega](https://tex.z-dn.net/?f=v%3Dr.%5Comega)
Putting respecstive values in eq. (1)
![L=m_E\times r^{2}\times \omega](https://tex.z-dn.net/?f=L%3Dm_E%5Ctimes%20r%5E%7B2%7D%5Ctimes%20%5Comega)
![L=5.97\times 10^{24}\times (1.5 \times 10^{11})^2\times \frac{2\pi}{3.156\times 10^7}](https://tex.z-dn.net/?f=L%3D5.97%5Ctimes%2010%5E%7B24%7D%5Ctimes%20%281.5%20%5Ctimes%2010%5E%7B11%7D%29%5E2%5Ctimes%20%5Cfrac%7B2%5Cpi%7D%7B3.156%5Ctimes%2010%5E7%7D)
![L=2.6742\times 10^{40}\, kg.m^2.s^{-1}](https://tex.z-dn.net/?f=L%3D2.6742%5Ctimes%2010%5E%7B40%7D%5C%2C%20kg.m%5E2.s%5E%7B-1%7D)
To model earth as a particle is reasonable because the distance between the sun and the earth is very large s compared to the radius if the earth.
(b)
For a uniform sphere of mass M and radius R and an axis through its center, ![I=\frac{2}{5}M.R^2](https://tex.z-dn.net/?f=I%3D%5Cfrac%7B2%7D%7B5%7DM.R%5E2)
using eq. (1)
![L_s=(\frac{2}{5}m_E.R_E^2) \omega](https://tex.z-dn.net/?f=L_s%3D%28%5Cfrac%7B2%7D%7B5%7Dm_E.R_E%5E2%29%20%5Comega)
![L_s=\frac{2}{5} \times 5.97\times 10^{24} \times 6.38\times 10^6\times \frac{2\pi}{86400}](https://tex.z-dn.net/?f=L_s%3D%5Cfrac%7B2%7D%7B5%7D%20%5Ctimes%205.97%5Ctimes%2010%5E%7B24%7D%20%5Ctimes%206.38%5Ctimes%2010%5E6%5Ctimes%20%5Cfrac%7B2%5Cpi%7D%7B86400%7D)
![L_s=7.07 \times 10^{23} \, kg.m^2.s^{-1}](https://tex.z-dn.net/?f=L_s%3D7.07%20%5Ctimes%2010%5E%7B23%7D%20%5C%2C%20kg.m%5E2.s%5E%7B-1%7D)
Answer:
Actions
Explanation:
if u mean what are these called then it's actions