The direction of friction force is always the opposite of the direction of the movement.
In this problem, we have an applied force of 20N and this creates a movement. Then, the friction comes in and applies a force of 2.4N.
Because they are in different directions, we need to subtract them:
We don't know the direction because there is no picture (at least I can't see ☺️). But the movement will be to the direction of the 20N.
Solution :
A vector is defined as an element that has magnitude of some measure and direction.
It is given there is vector 'd' which has magnitude 2.6 m and its direction is towards north.
a). -d
The magnitude of the vector '-d' is 2.6 m and its direction is reversed, i.e. its direction is towards south.
b). d/2.0
The magnitude of the vector 'd/2.0' is 1.3 m and its direction is towards north.
c). - 2.5d
The magnitude of the vector increases by 2.5 times i.e. 2.5 x 2.6 = 6.5 m and the direction is towards south.
d). 5.0d
The magnitude of the vector increases by 5 times i.e. 5 x 2.6 = 13 m and the direction is towards north.
Answer:
the force happens on the wall and couch
Explanation:
she is using her arm strength to lift and hold
Answer:
2.4*10^-17 J
Explanation:
E = V/d = 300 V / 3*10^-3 m = 1.0*10^5 V/m
Voltage at midpoint = E*d = 1.0*10^5 V/m * 1.5*10^-3 m = 150 V
ΔV = 300 V - 150 V = 150 V
Charge of a proton = 1.6*10^-16 C
U = qΔV = (1.6*10^-16 C)(150V) = 2.4*10^-17 J
Answer:
Distance, S = 440 meters.
Explanation:
Given the following data;
Initial velocity, u = 17m/s
Time, t = 20 seconds
Final velocity, v = 27m/s
To find the distance;
First of all, we would determine the acceleration of the truck.
Acceleration = (v-u)/t
Substituting the given values into the equation, we have;
Acceleration = (27 - 17)/20
Acceleration = 10/20
Acceleration = 0.5m/s²
Now, we would use the second equation of motion to find the distance traveled.
S = ut + ½at²
S = 17*20 + ½*0.5*20²
S = 340 + 0.25*400
S = 340 + 100
S = 440m